保存登录用户的外键作为外键

Question

所以我有3个表：用户，客户和预订。

各关系和外键：

用户有一个客户。客户属于用户。 Users.id = Customers.user_id

Customers hasMany Bookings。预订属于客户。 Customers.id = Bookings.customer_id

在添加表单中，当进行预订时，我想将登录用户的客户ID保存为预订的customer_id。

领域：

在用户表：

-id
-username
-password
-role_id (connected to roles table) -created
-modified

在Customers表：

-id
-user_id (the foreign key connected to Users table)
-name
-created
-modified

在登记表中：

-id
-customer_id (the foreign key connected to Customers table)
-payment_id (connected to payments table)
-created
-modified

Answer 1

你可以试试下面Ç颂

$booking = $this->Booking->newEntity(); 
if ($this->request->is('post')) { 
    $data = $this->request->data; #Store post data to a variable 
    $customer_id = #Find and assign customer ID to a variable 
    $data['customer_id'] = $customer_id; #Assign customer ID to saving data 
    $booking = $this->Bookings->patchEntity($booking, $data); 
    if ($this->Bookings->save($booking)) { 
     #SAVING SUCCESS 
    } else { 
     #ERROR SAVING 
    } 
} 

查找客户ID（加载模型）

$this->loadModel('Customers'); 
$logged_in_user_id = $this->Auth->user('id'); 
$customer = $this->Customers->find('all')->where(['user_id'=>$logged_in_user_id])->first(); 
$customer_id = $customer->id; #Or $customer['id']; 

查找客户ID（无负载模型）

$logged_in_user_id = $this->Auth->user('id'); 
$customer = $this->Bookings->Customers->find('all')->where(['user_id'=>$logged_in_user_id])->first(); 
$customer_id = $customer->id; #Or $customer['id']; 

Answer 2

退房的Footprint plugin，它处理准确这个问题相当透明。