2014-10-08 31 views
0

我有一个beagle骨,想从我的程序中读取gpio pin。该文件在任何时候都包含1或0。在我的C程序中,我有一个while循环,它永远运行一个休眠函数,以防止在该引脚处于低电平时(0),并且当它处于高电平时(1),它将运行代码。我觉得这是一个非常浪费资源。有没有一种方法可以在这个文件是1的时候看到,然后运行代码?我不喜欢投票,特别是当小猎犬骨头要用电池供电时。如何在没有轮询的情况下查找文件中的更改?

回答

0

使用通知机制,例如通过利用libev

基本思想是,如果数据可用,则调用回调。

如果这不起作用,您可能需要使用其他API才能达到此目的,例如inotify。 libev文档的

实施例提供:

// a single header file is required 
#include <ev.h> 

#include <stdio.h> // for puts 

// every watcher type has its own typedef'd struct 
// with the name ev_TYPE 
ev_io stdin_watcher; 
ev_timer timeout_watcher; 

// all watcher callbacks have a similar signature 
// this callback is called when data is readable on stdin 
static void 
stdin_cb (EV_P_ ev_io *w, int revents) 
{ 
puts ("stdin ready"); 
// for one-shot events, one must manually stop the watcher 
// with its corresponding stop function. 
ev_io_stop (EV_A_ w); 

// this causes all nested ev_run's to stop iterating 
ev_break (EV_A_ EVBREAK_ALL); 
} 

// another callback, this time for a time-out 
static void 
timeout_cb (EV_P_ ev_timer *w, int revents) 
{ 
puts ("timeout"); 
// this causes the innermost ev_run to stop iterating 
ev_break (EV_A_ EVBREAK_ONE); 
} 

int 
main (void) 
{ 
// use the default event loop unless you have special needs 
struct ev_loop *loop = EV_DEFAULT; 

// initialise an io watcher, then start it 
// this one will watch for stdin to become readable 
ev_io_init (&stdin_watcher, stdin_cb, /*STDIN_FILENO*/ 0, EV_READ); 
ev_io_start (loop, &stdin_watcher); 

// initialise a timer watcher, then start it 
// simple non-repeating 5.5 second timeout 
ev_timer_init (&timeout_watcher, timeout_cb, 5.5, 0.); 
ev_timer_start (loop, &timeout_watcher); 

// now wait for events to arrive 
ev_run (loop, 0); 

// break was called, so exit 
return 0; 
} 
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