我收到一个错误,返回一个200成功代码和parseerror响应的jQuery AJAX调用。我假设这意味着jQuery得到的数据,但无法解析它。但是,我可以检索响应数据,它是格式良好的JSON。AJAX返回200成功,但未能解析响应JSON
我正在使用jsonp数据进行跨域服务。
jQuery的
jQuery.ajax({
url: ServiceBasePath + "/json/ZipRiders",
dataType: "jsonp",
success: function (data) {
...
},
error: function (a,b,c) {
alert(a, b, c);
}
});
错误数据
a: Object { readyState=4, status=200, statusText="success", more...}
b: "parsererror"
c: Error: jQuery1101020726428059127155_1377610175566 was not called
响应
[
{
"AdDescription": "Taking 75 north instead of 23 just for fun",
"AdID": "---",
"CityName": "Highland",
"IsWanted": false,
"Latitude": "42.656281",
"Longitude": "-83.63297",
"Name": "Ride to Milford, MI",
"NetworkLogon": "---",
"RideNotifyEnable": true,
"UserName": "---"
},
{
"AdDescription": "Ride to jackson",
"AdID": "---",
"CityName": "Jackson",
"IsWanted": false,
"Latitude": "42.252268",
"Longitude": "-84.38842",
"Name": "Ride to Jackson, MI",
"NetworkLogon": "---",
"RideNotifyEnable": true,
"UserName": "---"
},
{
...
},
{
...
},
...
]
我想我们必须使用'$ .parseJSON()'使它成为JSON对象。 –
我可以看到完整的json数据吗 –
您正在指定'“jsonp”',但是您要返回JSON。他们不是一回事。 http://stackoverflow.com/questions/3839966/can-anyone-explain-what-jsonp-is-in-layman-terms/3840118#3840118 – Ian