grep搜索替换

-1

grep "^\[bugID[[:digit:]]\{1,\}\]"是第一行。我怎样才能grep为bugID或TICKET-grep搜索替换

[bugID12345] fix for performance issue 

[TICKET-12345] fix for memory leak issue 

[bugID23244] fix for performance issue 

[TICKET-54678] fix for memory leak issue

来源

2012-12-28 Vivek

please，rephrase你的问题，并使用4个空格来缩进代码;你的文章很难编辑 – Rubens

正如@rubens所说，请改述并提出一个问题 – simonmorley

egrep支持交替与|也[需求逃逸：

egrep "^\[(bugID|TICKET-)[[:digit:]]{1,}\]" file 
[bugID12345] fix for performance issue 
[TICKET-12345] fix for memory leak issue 
[bugID23244] fix for performance issue 
[TICKET-54678] fix for memory leak issue

如果你不想整条生产线都然后使用-o选项：

egrep -o "^\[(bugID|TICKET-)[[:digit:]]{1,}\]" file 
[bugID12345] 
[TICKET-12345] 
[bugID23244] 
[TICKET-54678]

来源

2012-12-28 12:25:25

感谢egrep解决方案的工作原理 – Vivek

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