查找单词在列表

我试图使一些发现，其中一个字是在列表中，然后告诉你在哪儿。这是我到目前为止有：查找单词在列表

whenAppears = 0 
when = [] 
i = 0 
phrase = str(input("What sentence? ")) 
phrase = phrase.lower() 
phrase = phrase.split() 
print(phrase) 
wordel = str(input("What single word would you like to find? ")) 
wordel = wordel.lower() 
if wordel in phrase: 
    print ("That word is in the phrase, there are",phrase.count(wordel),wordel+"('s)""in the sentence") 
for word in phrase: 
    whenAppears += 1 
    if wordel == phrase[i]: 
     when.append(whenAppears) 
print ("The word",wordel,"is in the slot",when)

不管我把它说这个词是在插槽1和任何其他插槽，我不能想到任何方式来这个，请帮助：D

来源

2016-02-02 Harry

看看在['list.index']（https://docs.python.org/3/library/stdtypes.html ＃common-sequence-operations）方法来更有效地找到项目列表中项目的位置。 –

将whenAppears += 1的if块之后。将wordel == phrase[i]更改为wordel == word。删除行i = 0。

更正代码：

whenAppears = 0 
when = [] 
phrase = str(input("What sentence? ")) 
phrase = phrase.lower() 
phrase = phrase.split() 
print(phrase) 
wordel = str(input("What single word would you like to find? ")) 
wordel = wordel.lower() 
if wordel in phrase: 
    print ("That word is in the phrase, there are",phrase.count(wordel),wordel+"('s)""in the sentence") 
for word in phrase: 
    if wordel == word: 
     when.append(whenAppears) 
    whenAppears += 1 
print ("The word",wordel,"is in the slot",when)

你可以让你的代码内涵和enumerate更好，但这些都是你一定要修复错误。

来源

2016-02-02 11:25:45 timgeb

非常感谢：DDDDDD !! – Harry

您以不正确的方式使用循环。您必须将wordel与word进行比较，因为任何时候循环使用phrase时，该值都将存储在word中。

for word in phrase: 
    whenAppears += 1 
    if wordel == word: 
     when.append(whenAppears)

来源

2016-02-02 11:25:16 k4ppa

您可以用list.index更有效地重写代码：

phrase = str(input("What sentence? ")).lower().split() 
print(phrase) 
wordel = str(input("What single word would you like to find? ")).lower() 
if wordel in phrase: 
    print ("That word is in the phrase, there are",phrase.count(wordel), wordel+"('s)""in the sentence") 
    print ("The word",wordel,"is in the slot", phrase.index(wordel))

来源

2016-02-02 11:30:26

查找单词在列表

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