bash一次选择多个答案

Question

我有一个平面文件称为项目，我想填充选择，但我希望能够一次选择多个项目。项目

文件内容：

cat 1 
dog 1 
pig 1 
cherry 2 
apple 2 

Basic脚本：

#!/bin/bash 
PS3=$'\n\nSelect the animals you like: ' 
options=$(grep '1' items|grep -v '^#' |awk '{ print $1 }') 

select choice in $options 
do 
    echo "you selected: $choice" 
done 

exit 0 

现在流动是我唯一可以在一次选择一个选项的方式。我希望能够回答1,3或1 3，并将它“您选择：猫猪”回应

谢谢

Tazmarine

Answer 1

这是我想出了。这似乎符合我的要求。我想用逗号分隔的最终输出：

#!/bin/bash 

newarray=(all $(grep '1' items|grep -v '^#' |awk '{ print $1 }')) 

options() { 
num=0 
for i in ${newarray[@]}; do 
    echo "$num) $i" 
    ((num++)) 
done 
} 

getanimal() { 
while [[ "$show_clean" =~ [A-Za-z] || -z "$show_clean" ]]; do 
    echo "What animal do you like: " 
    options 
    read -p 'Enter number: ' show 
    echo 
    show_clean=$(echo $show|sed 's/[,.:;]/ /g') 
    selected=$(\ 
    for s in $show_clean; do 
    echo -n "\${newarray[${s}]}," 
    done) 
    selected_clean=$(echo $selected|sed 's/,$//') 
done 
eval echo "You selected $selected_clean" 
} 

getanimal 

exit 0 

Answer 2

你不能这样做，因为这样，但你可以随时记录每个个体的选择：

#!/bin/bash 
PS3=$'\n\nSelect the animals you like: ' 
options=$(grep '1' items|grep -v '^#' |awk '{ print $1 }') 

# Array for storing the user's choices 
choices=() 

select choice in $options Finished 
do 
    # Stop choosing on this option 
    [[ $choice = Finished ]] && break 
    # Append the choice to the array 
    choices+=("$choice") 
    echo "$choice, got it. Any others?" 
done 

# Write out each choice 
printf "You selected the following: " 
for choice in "${choices[@]}" 
do 
    printf "%s " "$choice" 
done 
printf '\n' 

exit 0 

下面是一个例子互动：

$ ./myscript 
1) cat 
2) dog 
3) pig 
4) Finished 

Select the animals you like: 3 
pig, got it. Any others? 

Select the animals you like: 1 
cat, got it. Any others? 

Select the animals you like: 4 
You selected the following: pig cat 

如果改为希望能够在同一行上写3 1，你必须使自己的菜单循环与echo和read