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我有,我环路通过嵌套表对象的列表,而且我显示的物品反复使用嵌套的for循环播放模板。递归在游戏框架2.5.X
-skillList是一个列表[技巧]
-Skill是()在模型
-skillObject.getChildrenList定义的对象返回一个列表[技巧]
我想do是能够显示这个,但使用某种类型的递归,以便如果mylist的嵌套级别发生变化,我不必更改整个模板。那么有什么办法以递归的方式做到这一点?
<div class="custom-dd dd dd-nodrag" id="nestable_list_1">
<ol class="dd-list">
@for(skill <- skillList) {
<li class="dd-item">
<div class="dd-handle dd-nodrag row">
<span class="dd-nodrag" id="[email protected]()"> @skill.getLabel() </span>
</div>
<ol class="dd-list">
@for((child, indexChild) <- skill.getChildrenList().zipWithIndex) {
<li class="dd-item" data-id="@indexChild">
<div class="dd-handle dd-nodrag row">
<span id="[email protected]()"> @child.getLabel() </span>
</div>
<ol class="dd-list">
@for((grandChild, indexGrandChild) <- child.getChildrenList().zipWithIndex) {
<li class="dd-item" data-id="@indexGrandChild">
<div class="dd-handle dd-nodrag row">
<span id="[email protected]()"> @grandChild.getLabel() </span>
</div>
</li>
}
<div class="text-left addNew" id="[email protected]">
<span>
<button class="btn btn-icon w-xs plusBtn
btn-primary waves-effect waves-light toggleButton" data-toggle="modal"
data-target="#custom-width-modal"> <i class="fa fa-plus" aria-hidden="true"></i>
</button>
</span>
</div>
@(index = index + 1)
</ol>
</li>
}
</ol>
</li>
}
</ol>
先谢谢您的任何答复。