我有下面的表格条目。Postgres按日期分组(时间戳)和总和值。
mydb=> SELECT username, input_bytes, output_bytes, updated_at from radius_acct;
username | input_bytes | output_bytes | updated_at
----------+-------------+--------------+------------------------
sandeep | 255081 | 42154 | 2014-05-08 09:34:13+00
sandeep | 250281 | 42254 | 2014-05-09 09:34:14+00
prashant | 258081 | 42354 | 2014-05-10 09:34:15+00
arun | 493 | 1215 | 2014-05-17 11:16:53+00
arun | 9421 | 3657 | 2014-05-17 11:21:38+00
arun | 18325 | 4504 | 2014-05-17 17:12:53+00
prashant | 254081 | 42454 | 2014-05-11 09:34:16+00
raj | 255081 | 42554 | 2014-05-12 09:34:17+00
raj | 250681 | 42554 | 2014-05-13 09:34:18+00
raj | 253081 | 42654 | 2014-05-14 09:34:19+00
kumar | 295081 | 47254 | 2014-05-15 09:34:16+00
(11 rows)
我想总结输入和输出字节并以MB为单位显示它,并按日期分组用户名。
我的查询不分组的日期和概括起来,并显示类似的输出如下所示:
mydb=> SELECT username, input_bytes, output_bytes, ROUND((SUM(input_bytes + output_bytes)/1048576)::decimal, 2) AS total, date(updated_at) from radius_acct group by username, input_bytes, output_bytes, updated_at ORDER BY username ASC ;
username | input_bytes | output_bytes | total | date
----------+-------------+--------------+-------+------------
arun | 493 | 1215 | 0.00 | 2014-05-17
arun | 9421 | 3657 | 0.01 | 2014-05-17
arun | 18325 | 4504 | 0.02 | 2014-05-17
kumar | 295081 | 47254 | 0.33 | 2014-05-15
prashant | 254081 | 42454 | 0.28 | 2014-05-11
prashant | 258081 | 42354 | 0.29 | 2014-05-10
raj | 250681 | 42554 | 0.28 | 2014-05-13
raj | 253081 | 42654 | 0.28 | 2014-05-14
raj | 255081 | 42554 | 0.28 | 2014-05-12
sandeep | 250281 | 42254 | 0.28 | 2014-05-09
sandeep | 255081 | 42154 | 0.28 | 2014-05-08
预期输出:
username | input_bytes | output_bytes | total | date
----------+-------------+--------------+-------+------------
**arun | 28239 | 9376 | 0.03 | 2014-05-17**
kumar | 295081 | 47254 | 0.33 | 2014-05-15
prashant | 254081 | 42454 | 0.28 | 2014-05-11
prashant | 258081 | 42354 | 0.29 | 2014-05-10
raj | 250681 | 42554 | 0.28 | 2014-05-13
raj | 253081 | 42654 | 0.28 | 2014-05-14
raj | 255081 | 42554 | 0.28 | 2014-05-12
sandeep | 250281 | 42254 | 0.28 | 2014-05-09
sandeep | 255081 | 42154 | 0.28 | 2014-05-08
行一个阿伦是一共三个行。
我看你有没有接受任何答案,直到日期,尽管它帮助的。请接受几个对你有帮助的答案,并且尊重他人的努力。一路上你自己也得到一些代表。 – Rahul