Spring-Security DAOAuthenticationProvider要求身份验证

Question

我在Spring-MVC应用程序之上使用Spring-Security。我有我自己的UserDAO，userDetailsS​​ervice的实现。我试图通过从数据库检查（ofcourse）进行身份验证。我到达直到登录页面，一切似乎都做工精细，但当我登录，我得到一个错误：

错误：

org.springframework.security.web.authentication.UsernamePasswordAuthenticationFilter - An internal error occurred while trying to authenticate the user. 
org.springframework.security.authentication.InternalAuthenticationServiceException: Provided id of the wrong type for class com.WirTauschen.model.User. Expected: class java.lang.Integer, got class java.lang.String 
    at org.springframework.security.authentication.dao.DaoAuthenticationProvider.retrieveUser(DaoAuthenticationProvider.java:110) 

我不知道我在哪里获取或者利用用户的id工作。我张贴下面的代码。

login服务：

@Service("userDetailsService") 
public class LoginServiceImpl implements UserDetailsService{ 
    @Autowired private UserDao userDao; 
    @Autowired private Assembler assembler; 

    @Override 
    @Transactional 
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException { 
      UserDetails userDetails = null; 

     User user = userDao.findByName(username); 
      if(user == null) { throw new UsernameNotFoundException("Wrong username or password");} //Never specify which one was it exactly 
     return assembler.buildUserFromUserEntity(user); 
    } 
} 

汇编

@Service("assembler") 
public class Assembler { 
    @Transactional(readOnly = true) 
    User buildUserFromUserEntity(com.WirTauschen.model.User userEntity){ 
     String username = userEntity.getUsername(); 
     String password = userEntity.getPassword(); 
     // int id = userEntity.getId(); 
     boolean enabled = userEntity.isActive(); 
     boolean accountNonExpired = userEntity.isAccountNonExpired(); 
     boolean credentialsNonExpired = userEntity.isCredentialsNonExpired(); 
     boolean accountNonLocked = userEntity.isAccountNonLocked(); 

     Collection<GrantedAuthority> authorities = new ArrayList<GrantedAuthority>(); 
     authorities.add(new SimpleGrantedAuthority("ROLE_USER")); 

     User user1 = new User(username,password,enabled,accountNonExpired,credentialsNonExpired,accountNonLocked,authorities); 
     return user1; 
     } 
} 

用户：

@Entity 
@Table(name="registration") 
public class User implements UserDetails{ 
    private static final GrantedAuthority USER_AUTH = new SimpleGrantedAuthority("ROLE_USER"); 

    @Id 
    @Column(name="id") 
    private String id=UUID.randomUUID().toString(); 
    // @GeneratedValue(strategy = GenerationType.SEQUENCE,generator = "my_entity_seq_gen") 
    //@SequenceGenerator(name ="my_entity_seq_gen", sequenceName = "MY_ENTITY_SEQ") 


    @OneToMany 
    private Set<ProductBasic> productBasic; 

    @Column(name = "email") 
    private String email; 

    @Column(name = "username") 
    private String Username; 

    @Column(name = "displayname") 
    private String DisplayName; 

    @Column(name = "password") 
    private String password; 

    @Column(name = "companyname") 
    private String CompanyName; 

    @Column(name = "firstname") 
    private String FirstName; 

    @Column(name = "middlename") 
    private String MiddleName; 

private String role="ROLE_USER"; 


    @Transient 
    private final String PERMISSION_PREFIX = "ROLE_USER"; 
    @Transient 
    private List<GrantedAuthority> authorities; 
    public User() { 
      this.authorities = new ArrayList<GrantedAuthority>(); 
      authorities.add(USER_AUTH); 
    } 

    public User(String Username, String password, String Role){ 
     this.Username = Username; 
     this.password = password; 
     this.role = Role; 
     if((role == null) || role.isEmpty()){ role = "ROLE_USER";} 

    } 

@Override 
    public Collection<? extends GrantedAuthority> getAuthorities() { 
     return authorities; 
    } 

更新序列码

@Id 
@Column(name = "sortcanvasid") 
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sortcanvas_gen") 
@SequenceGenerator(name = "sortcanvas_gen", sequenceName = "sortcanvas_seq") 
private int sortCanvasId; 

Answer 1

似乎你的User类没有实现UserDetails Morever它可能没有正确的返回类型的getID方法