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我试图陷入一个http请求,改变它的一些post参数并发送修改后的请求。 我尝试使用上传流的setData方法来修改请求,但发送了相同的原始请求。修改firefox扩展中的请求的发布数据
我有下面的代码执行在“HTTP上 - 修改 - 请求”:
//rewind the request to read post body
channel= subject.QueryInterface(Components.interfaces.nsIHttpChannel);
channel=channel.QueryInterface(Components.interfaces.nsIUploadChannel);
channel = channel.uploadStream;
channel.QueryInterface(Components.interfaces.nsISeekableStream)
.seek(Components.interfaces.nsISeekableStream.NS_SEEK_SET, 0);
var stream = Components.classes["@mozilla.org/binaryinputstream;1"]
.createInstance(Components.interfaces.nsIBinaryInputStream);
stream.setInputStream(channel);
var postBytes = stream.readByteArray(stream.available());
poststr = String.fromCharCode.apply(null, postBytes);
//change the poststr
poststr=poststr.replace(....);
stringStream.setData(poststr, poststr.length);
//changing the postdata
channel = channel.QueryInterface(Components.interfaces.nsIUploadChannel);
channel = channel.uploadStream;
channel = channel.QueryInterface(Components.interfaces.nsISeekableStream)
.seek(Components.interfaces.nsISeekableStream.NS_SEEK_SET, 0);
channel.uploadStream.QueryInterface(Components.interfaces.nsIMIMEInputStream);
channel.uploadStream.setData(stringStream);
channel.send();
我在做什么错在这里? 我试图放弃最初的请求,并从一个新的请求开始,但然后页面根本不加载。 Thanx提前。
你可以使用`{}`按钮来让你的代码看起来像代码时,问一个问题。 – MatrixFrog 2011-02-01 01:10:38