spring-roo为错误的@id属性名创建json控制器

我即将评估spring roo，而我正在对现有的mysql数据库方案进行反向工程。除了web mvc json all命令在某些情况下创建的*_Roo_Controller_Json.aj文件引用了不存在的JPA实体获取方：getId()之外，一切运行良好。这似乎发生在以@Id注释的字段的名称与id不同的情况下。奇怪的是，当我通过执行整个roo脚本从头开始创建应用程序时，并不总是出现这个问题（在下面发布）。spring-roo为错误的@id属性名创建json控制器

的JPA实体ITD看起来像：

privileged aspect FrmwrkAuthItem_Roo_Jpa_Entity { 

    declare @type: FrmwrkAuthItem: @Entity; 

    declare @type: FrmwrkAuthItem: @Table(name = "frmwrk_AuthItem"); 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    @Column(name = "name", length = 64) 
    private String FrmwrkAuthItem.name; 

    public String FrmwrkAuthItem.getName() { 
     return this.name; 
    } 

    public void FrmwrkAuthItem.setName(String id) { 
     this.name = id; 
    } 
}

web mvc json all命令创建带有createFromJson()方法，其中所述非现有吸气剂getId()被使用（简化代码）文件FrmwrkAuthItemController_Roo_Controller_Json.aj。

privileged aspect FrmwrkAuthItemController_Roo_Controller_Json { 

    ... 

    @RequestMapping(method = RequestMethod.POST, headers = "Accept=application/json") 
    public ResponseEntity<String> FrmwrkAuthItemController.createFromJson(@RequestBody String json, UriComponentsBuilder uriBuilder) { 
     HttpHeaders headers = new HttpHeaders(); 
     headers.add("Content-Type", "application/json"); 
     try { 
      FrmwrkAuthItem frmwrkAuthItem = FrmwrkAuthItem.fromJsonToFrmwrkAuthItem(json); 
      frmwrkAuthItemService.saveFrmwrkAuthItem(frmwrkAuthItem); 
      RequestMapping a = (RequestMapping) getClass().getAnnotation(RequestMapping.class); 

      /******************************************** 
      * below is the corrupt line of code with frmwrkAuthItem.getId() 
      * frmwrkAuthItem.getName() would be correct! 
      ********************************************/ 
      headers.add("Location",uriBuilder.path(a.value()[0]+"/"+frmwrkAuthItem.getId().toString()).build().toUriString()); 

      return new ResponseEntity<String>(headers, HttpStatus.CREATED); 
     } catch (Exception e) { 
      return new ResponseEntity<String>("{\"ERROR\":"+e.getMessage()+"\"}", headers, HttpStatus.INTERNAL_SERVER_ERROR); 
     } 

     ....

在Roo脚本来创建应用程序是：

project --topLevelPackage org.myproject 
jpa setup --provider ECLIPSELINK --database MYSQL --databaseName myproject --userName *** --password *** 
addon install bundle --bundleSymbolicName org.springframework.roo.wrapping.mysql-connector-java 

database reverse engineer --schema myproject --service --package ~.domain 
json all 
web mvc setup --package ~.contoller 
web mvc all --package ~.contoller 
web mvc json all

来源

2015-02-10 Andreas Kohlbecker