2017-06-01 120 views
2

我尝试从我的日志文件中获取一个数字。这个数字是在每个“当前商店使用率”之后。我怎样才能做到这一点?我可以使用re模块吗?从日志文件在文本文件中搜索数字?

线

2017-05-30 12:01:03,168 | WARN | Store limit is 102400 mb (current store usage is 0 mb). The data directory: /opt/apache-activemq-5.12.0/bin/linux-x86-64/../../data only has 6887 mb of usable space - resetting to maximum available disk space: 6887 mb | org.apache.activemq.broker.BrokerService | WrapperSimpleAppMain 

我的代码

def log_parser(): 
    palab2 = "WARN" 
    logfile = open("/opt/apache-activemq-5.12.0/data/activemq.log", "r") 
    contenlog = logfile.readlines() 
    logfile.close() 
    for ligne in contenlog: 
     if palab2 in ligne: 
      print ("Probleme : " + ligne) 
+1

不要使用'readlines'读取整个文件。你可以遍历每一行。是的,你可以使用're'。 –

回答

0

是的,你可以使用re模块来大大简化这一点。并且+1到@Eric Duminil表示建议不要一次读取整个文件。

import re 

def log_parser(): 
    palab2 = "WARN" 
    logfile = "/opt/apache-activemq-5.12.0/data/activemq.log" 

    with open(logfile, 'r') as contenlog: 
     for ligne in contenlog: 
      if re.findall(palab2, ligne): 
       print ("Probleme : " + ligne) 
       break 
1

这会为你工作:

import re 
ligne = '2017-05-30 12:01:03,168 | WARN | Store limit is 102400 mb (current store usage is 0 mb). The data directory: /opt/apache-activemq-5.12.0/bin/linux-x86-64/../../data only has 6887 mb of usable space - resetting to maximum available disk space: 6887 mb | org.apache.activemq.broker.BrokerService | WrapperSimpleAppMain' 
print(re.search(r'current store usage is (\d+)', ligne).group(1)) 
# this returns a 'string', you can convert it to 'int' 

输出:

'0' 

快乐编码!!!

0

试试这个:

import re 

def log_parser(): 
    with open("/opt/apache-activemq-5.12.0/data/activemq.log", "r") as logfile: 
     for line in logfile: 
      m = re.search(r"current store usage is (\d+)", line): 
       if m: 
        return m.group(1) 

print(log_parser()) 

,如果你只想要第一次出现(我假设的话)或所有这些文件中的行没有指定。如果后者为真,只需将return更改为yield,然后调用如下函数:print(list(log_parser()))