我有以下两个查询:SQL:结合两个查询到一个单一的一个
Select count(project.id) as num_project ,
industry.name as industry_name
from project, project_industry, industry
where industry.id= project_industry.industry_id and
project.id = project_industry.project_id
group by industry.id;
Select count(user.id) as num_consultants ,
industry.name as industry_name
from consultant_profile, industry_experience,user, industry
where industry_experience.consultant_profile_id = consultant_profile.id
and industry_experience.industry_id= industry.id
and user.type=0
and user.is_active=1
and consultant_profile.user_id=user.id
group by industry_id;
我试图将它们组合成一个单一的一个如下:
SELECT i.name AS industry_name, num_projects, num_consultants
FROM industry i
JOIN (SELECT pc.industry_id, COUNT(p.id) AS num_projects
FROM project p
JOIN project_industry pc ON p.id = pc.project_id
GROUP BY pc.industry_id) x ON x.industry_id = i.id
JOIN (SELECT y.industry_id, COUNT(u.id) AS num_consultants
FROM user u, consultant_profile cp
JOIN project_experience pe on pe.consultant_profile_id = cp.id
WHERE u.is_active = 1 AND u.type = 0
GROUP BY y.industry_id) z ON z.industry_id = i.id;
但似乎没有工作。有人能指出我做错了什么吗?任何帮助深表感谢。
编辑:要说清楚第一个查询显示与每个行业相关的项目数量。第二个查询显示与每个行业相关的顾问数量。
我想第三个查询,以显示从同一表中的第一两个查询上3个单独的列中的信息:行业名称,#Projects,#Consultants
表结构是如下,其中 - >描述该表的主键和外键:
Project -> project.id
Project_industry -> project_industry.id, project_id, industry_id
Industry -> industry.id
user -> user.id
Consultant_profile -> consultant_profile.id, user_id
Industry_Experience -> industry_experience.id, consultant_profile_id, industry_id
Industry -> industry.id
你能告诉我们你的表结构,你想要得到的输出? – Aurel
结合如何?向我们显示您想要组合的两个查询中的几行,以及组合结果。 – jarlh
你确定你的第二个查询是正确的吗?请交叉检查'我'是否是任何表的别名 – saikumarm