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我创建从MySQL查询PHP表如下:PHP超链接/弹出表
$resultkulim = mysql_query("SELECT customer_name, zone_name, segment_code, COUNT(segment_code) FROM complete_wk where zone_name = 'ZONE KULIM' and (segment_code = 's30' or segment_code='s40' or segment_code='s50'')");
$totalrrkulim = mysql_query("SELECT zone_name, repeat_rc, COUNT(repeat_rc) FROM complete_wk where zone_name = 'ZONE KULIM' and repeat_rc>1 and (segment_code = 's30' or segment_code='s40' or segment_code='s50')");
echo "<table class='table1'>";
echo "<thead>";
echo "<tr>";
echo "<th>Zone</th>";
echo "<th>Total TR</th>";
echo "<th>Total RR (RR>1)</th>";
echo "<th>%RR</th>";
echo "</tr>";
echo "</thead>";
//kulim row
while($rowkulim = mysql_fetch_array($resultkulim))
{
echo "<tbody>";
echo "<tr>";
echo "<td>Zone Kulim</td>";
echo "<td >" . $rowkulim['COUNT(segment_code)'] . "</td>";
while($rrkulim = mysql_fetch_array($totalrrkulim))
{
$myresultkulim = $rrkulim['COUNT(repeat_rc)']/$rowkulim['COUNT(segment_code)'] * 100;
echo "<td>" . $rrkulim['COUNT(repeat_rc)'] . "</td>";
echo "<td>" . number_format($myresultkulim) . "%" . "</td>";
echo "</tr>";
echo "</tbody>";
}
}
echo "</table>";
而且表的例子结果如下:
Zone Total TR Total RR %RR
Zone Kulim 182 11 6%
我想要做的是,我希望能够点击Total TR的结果,即“182”,它会将我带到包含该结果细节表的其他页面。
我已经做了其他表,它位于“本地主机/ TMJ/index.php文件/ TR/Kulim的”
我希望有人能赐教如何要么使一个弹出窗口或超链接到上面表格代码中的其他页面。