使用PHP在没有卷标的情况下进行PayPal API调用

Question

由于Google App Engine不支持，我无法使用cURL。

我想获得在步骤2中的访问令牌：https://developer.paypal.com/docs/integration/direct/make-your-first-call

我不知道我应该怎么构建我的电话。我有这个至今：

$data = array(
    'grant_type' => 'client_credentials', 
    'client_id' => $sandbox_client_id, 
    'secret' => $sandbox_secret 

); 


$data = json_encode($data); 

$context = [ 
    'http' => [ 
    'method' => 'POST', 
    'header' => 'Content-Type: application/x-www-form-urlencoded' . "\r\n" . 
     'Accept: application/json' . "\r\n" . 
     'Accept-Language: en_US' . "\r\n" 
    , 
    'content' => $data 
    ] 
]; 
$context = stream_context_create($context); 

$response = file_get_contents('https://api.sandbox.paypal.com/v1/oauth2/token', false, $context); 

echo $response; 

它返回这样的：

Warning: file_get_contents(https://api.sandbox.paypal.com/v1/oauth2/token): failed to open stream: HTTP request failed! HTTP/1.1 401 Unauthorized in C:\folder\php\paypal\test.php on line 28 

任何有识之士的赞赏！

Answer 1

我想通了。

client id和secret必须放入由:，然后base64 encoded分开的字符串中。然后发送到header。

这工作：

$auth_string = $sandbox_client_id . ':' . $sandbox_secret; 
$encoded_auth = base64_encode($auth_string); 

$data = array(
    'grant_type' => 'client_credentials' 


); 

$http_query = http_build_query($data); 
$context = [ 
    'http' => [ 
    'method' => 'POST', 
    'header' => 'Content-Type: application/x-www-form-urlencoded' . "\r\n" . 
     'Accept: application/json' . "\r\n" . 
     'Accept-Language: en_US' . "\r\n" . 
     'Authorization: Basic ' . $encoded_auth 
    , 
    'content' => $http_query 
    ] 
]; 


$context = stream_context_create($context); 

$response = file_get_contents('https://api.sandbox.paypal.com/v1/oauth2/token', false, $context); 

echo $response;