我有for循环和glob和os模块的问题。 在python Shell中打印出来,但是当我在php中嵌入python脚本时,它不起作用。Python脚本在PHP中运行时跳过与os和glob模块的线
通过PHP下面的python只打印“第一”和“第二”,但不打印“当前文件是:...”。
也许我找到另一种方式来阅读目录? glob和os模块与PHP不兼容?
蟒蛇:
print("first")
path = 'cat/tryfile'
for infile in glob.glob(os.path.join(path, '*.jpg')):
print("current file is: " + infile)
print("second")
PHP:
$param1 = "first";
$param2 = "second";
$param3 = "third";
$command = "C:\\python27\\python C:\\Python27\\execprova.py";
#FIRST PYTHON embedding with popen
$command .= " $param1 $param2 $param3 2>&1";
$temp = exec($command, $return);
echo "INIZIO PID";
$pid = popen($command,"r");
echo "<body><pre>";
while(!feof($pid))
{
echo fread($pid, 256);
flush();
ob_flush();
usleep(100000);
}
pclose($pid);
#SECOND PYTHON embedding with exec
echo (" {PHP inizio command output return ed exec /PHP} ");
$command = "C:\\python27\\python C:\\Python27\\bp1imgsenzaprint.py";
$output = null;
$temp = exec($command);
function success()
{
$mystring = exec('C:\\python27\\python C:\\Python27\\bp1imgsenzaprint.py', $output);
var_dump($output);
var_dump($mystring);
print_r($output);
}
print("SUCCESS");
success();
在Python脚本的'path'变量中使用绝对路径而不是相对? –
是的,现在它的作品! – postgres