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我创建了以下情形列名:JPA:@ElementCollection和InheritanceType.TABLE_PER_CLASS - >复制
@javax.persistence.Entity
@Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)
public class MyEntity implements Serializable{
@Id
@GeneratedValue
protected Long id;
...
@ElementCollection
@CollectionTable(name="ENTITY_PARAMS")
@MapKeyColumn (name = "ENTITY_KEY")
@Column(name = "ENTITY_VALUE")
protected Map<String, String> parameters;
...
}
除了:
@javax.persistence.Entity
public class Sensor extends MyEntity{
@Id
@GeneratedValue
protected Long id;
...
// so here "protected Map<String, String> parameters;" is inherited !!!!
...
}
那么运行这个例子,没有空桌,创建并且我得到以下消息:
WARNUNG: Got SQLException executing statement "CREATE TABLE ENTITY_PARAMS (Entity_ID BIGINT NOT NULL, ENTITY_VALUE VARCHAR(255), ENTITY_KEY VARCHAR(255), Sensor_ID BIGINT NOT NULL, ENTITY_VALUE VARCHAR(255))": com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Duplicate column name 'ENTITY_VALUE'
我也尝试覆盖Sens上的属性或类...
@AttributeOverrides({
@AttributeOverride(name = "ENTITY_KEY", column = @Column(name = "SENSOR_KEY")),
@AttributeOverride(name = "ENTITY_VALUE", column = @Column(name = "SENSOR_VALUE"))
})
......但同样的错误。
编辑:
好吧,我已经发现,与“联合”,以及与继承策略“SINGLE_TABLE”一切工作正常。此外,它似乎与EclipseLink版本无关 - 我试过1.3和2.0.1。
END_EDIT
任何人可以帮助我吗?