7
我有以下xPath从<div class="separator">获取图像。我的问题是我怎样才能使xPath在<div class="entry">也搜索？XPath选择器中是否存在“或”？
$img = $xpath->query('//div[@class="separator"]//img');
感谢提前:)
A
回答
7
$img = $xpath->query('//div[@class="separator" or @class="entry"]//img');
感谢嗨它的作品！然而，我有另一个小问题'$ posts = $ xPath-> query（'// item'）; foreach（$ posts as $ post）{ $ title = $ post-> getnode（'title'）; ' 我可以放什么而不是'getnode'（这是错误的）从- 得到
的值？ –
<span class="text-secondary">
<small>
<a rel="noopener" target="_blank" href="https://stackoverflow.com/users/807325/">EnexoOnoma</a></span>
<span>2011-03-29 04:00:49</span>
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<div class="col-lg-1"><span class="text-secondary">+1</span></div>
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<p class="commenttext">@Mikey如果您想要HTML元素的文本节点，请尝试'nodeValue'属性。如果你想'title'元素，请尝试'getElementsByTagName（'title'）'。 –
<span class="text-secondary">
<small>
<a rel="noopener" target="_blank" href="https://stackoverflow.com/users/31671/">alex</a></span>
<span>2011-03-29 04:07:44</span>
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<div class="col-lg-1"><span class="text-secondary">+0</span></div>
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<p class="commenttext">嗨，亚历克斯，再次感谢。它真的帮助我，并根据您的答案正确更改了我的整个代码！然而，我有一个关于属性的小问题，如果你有时间看看[http://stackoverflow.com/questions/5467957/error-on-getting-src-attribute-question-on-how-to-get-正确的路径] –
<span class="text-secondary">
<small>
<a rel="noopener" target="_blank" href="https://stackoverflow.com/users/807325/">EnexoOnoma</a></span>
<span>2011-03-29 04:41:52</span>
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<pre><code class="prettyprint-override">$img = $xpath->query('//div[@class="separator"]//img | //div[@class="entry"]//img');
</code></pre>
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<a rel="noopener" target="_blank" href="https://stackoverflow.com/q/5467592">来源</a>
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<span>2011-03-29 03:29:28</span>
<a rel="noopener" target="_blank" href="https://stackoverflow.com/users/675065/">Alp</a></span>
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<pre><code class="prettyprint-override">$img = $xpath->query('//div[@class="separator" or @class='entry']//img');
</code></pre>
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