将列转换为行，使用分隔符“ - ”，“;”

-1

 select(Emp_no, ADate, Atime)

 12333,  12-02-2013, 09.12 - 12.30 
     12333,  12-02-2013, 12.32 - 17.30 

     13444,  12-02-2013, 09.10 - 18.30 

     14444,  12-02-2013, 09.13 - 12.30 
     14444,  12-02-2013, 17.20

输出：

 12333,  12-02-2013, 09.12 - 12.30 ; 12.32 - 17.30 
     13444,  12-02-2013, 09.10 - 18.30 
     14444,  12-02-2013, 09.13 - 12.30 ; 17.20

请帮助我，

问候， Nirmal.M

来源

2013-02-19 Nirmal

您可以使用与此类似，以多行连接成单行：

select distinct t1.Emp_no, 
    t1.ADate, 
    STUFF(
     (SELECT '; ' + cast(t2.Atime as varchar(50)) 
      FROM yourtable t2 
      where t1.Emp_no = t2.Emp_no 
      and t1.ADate = t2.ADate 
      FOR XML PATH ('')) 
      , 1, 1, '') AS Atime 
from yourtable t1

见SQL Fiddle with Demo

或者你可以使用一个CROSS APPLY与FOR XML PATH：

select distinct t1.Emp_no, 
    t1.ADate, 
    left(t2.Atime, len(t2.atime)-1) ATime 
from yourtable t1 
cross apply 
(
    select t2.Atime + '; ' 
    from yourtable t2 
    where t1.Emp_no = t2.Emp_no 
    and t1.ADate = t2.ADate 
    FOR XML PATH('') 
) t2 (Atime)

见SQL Fiddle with Demo

来源

2013-02-19 13:58:53 Taryn

将列转换为行，使用分隔符“ - ”，“;”

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