将以下SWITCH语句转换为IF ... ELSE语句

Question

b）将以下switch语句转换为if ... else语句。

#include <stdio.h> 
void main() 
{ 
    char option; 
    int a; 
    printf("a.Addition\n b.Subtraction\n c.Multiplication\n d.Division\n"); 
    printf("Choose your option : "); 
    scanf("%c",&option); 

    switch(option) 
    { 
    case 'a': 
    case 'A': a=20+10; 
     printf("Addition process result:%d",a); 
     break; 
    case 'b': 
    case 'B': a=20-10; 
     printf("Subtraction process result:%d",a); 
     break; 
    case 'c': 
    case 'C': a=20*10; 
     printf("Multiplication process result:%d",a); 
     break; 
    case 'd': 
    case 'D': a=20/10; 
     printf("Division process result:%d",a); 
     break; 
    default: printf("Invalid option"); 
    } 
    printf("\nEnd of program"); 

} 

如何将其从SWITCH转换为IF ... ELSE？ 这是我的考试 修订问题，谢谢

Answer 1

一个switch声明可被看作是一系列if/else条款。下面是这应该有助于您解决具体问题的例子：

switch (x) 
{ 
    case 1: 
    case 2: 
     foo(); 
     break;  

    case 3: 
    case 4: 
     bar(); 
     break;  

    default: 
     blech(); 
     break;  
} 

变为：

if (x == 1 || x == 2)   // case 1: 
{        // case 2: 
    foo(); 
} 
else if (x == 3 || x == 4) // case 3: 
{        // case 4: 
    bar(); 
} 
else       // default: 
{ 
    blech(); 
} 

Answer 2

if(option == 'a' ||option == 'A') //checks if option value is 'a' or 'A',in switch case you use case:a,and case:b 
    { 
    a=20+10;  
    printf("Addition process result:%d",a); 
    } 
else if(option == 'b' ||option == 'B')  
    { 
    a=20-10; 
    printf("Subtraction process result:%d",a); 
    } 
else if(option == 'c' ||option == 'C')  
    { 
    a=20*10; 
    printf("Multiplication process result:%d",a); 
    } 
else if(option == 'd' ||option == 'D')  
    { 
    a=20/10; 
    printf("Division process result:%d",a); 
    } 
else 
    { 
     printf("Invalid option"); 
    } 

我怎么转化：

1：中改变了所有cases有条件的陈述在if

例如：

switch(option) 
{ 
    case 'a': 
    case 'A':some statement; 
     break; 
} 

到

if(option == 'a' || option == 'A') 
    { 

    some statement; 
    } 

Answer 3

#include <stdio.h> 
void main() 
{ 
    char option; 
    int a; 
    printf("a.Addition\n b.Subtraction\n c.Multiplication\n d.Division\n"); 
    printf("Choose your option : "); 
    scanf("%c",&option); 

    if (option == 'a' || option == 'A') { 
     printf("Addition process result:%d",a); 
    } 
    elseif (option == 'b' || option == 'B') { 
     printf("Subtraction process result:%d",a); 
    } 
    elseif (option == 'c' || option == 'C') { 
     printf("Multiplication process result:%d",a); 
    } 
    elseif (option == 'd' || option == 'D') { 
     printf("Division process result:%d",a); 
    } 
    else { 
     printf("Invalid option"); 
    } 
    printf("\nEnd of program"); 

} 

这是你的问题的解决方案。