我知道我以前在某个地方见过一些例子，但对于我的生活，我无法在Google搜索时找到它。如何在Jupyter笔记本中将列表输出为表格？
我有数据的某些行：
data = [[1,2,3],
[4,5,6],
[7,8,9],
]
我想输出的表格，例如这个数据
+---+---+---+
| 1 | 2 | 3 |
+---+---+---+
| 4 | 5 | 6 |
+---+---+---+
| 7 | 8 | 9 |
+---+---+---+
很明显，我可以使用像可爱的图书馆或下载熊猫或其他东西，但我很无心这样做。
我只想在我的Jupyter笔记本电脑中输出我的行作为表格。我该怎么做呢？
我终于重新找到了jupyter/IPython documentation，我一直在寻找对。
，我需要这样的：
from IPython.display import HTML, display
data = [[1,2,3],
[4,5,6],
[7,8,9],
]
display(HTML(
'<table><tr>{}</tr></table>'.format(
'</tr><tr>'.join(
'<td>{}</td>'.format('</td><td>'.join(str(_) for _ in row)) for row in data)
)
))
（我可能会稍微打乱了的解析，但display(HTML('some html here'))是我们所需要的）
你可以尝试使用下面的函数
def tableIt(data):
for lin in data:
print("+---"*len(lin)+"+")
for inlin in lin:
print("|",str(inlin),"", end="")
print("|")
print("+---"*len(lin)+"+")
data = [[1,2,3,2,3],[1,2,3,2,3],[1,2,3,2,3],[1,2,3,2,3]]
tableIt(data)
好了，所以这是一个有点难度比我还以为：
def print_matrix(list_of_list):
number_width = len(str(max([max(i) for i in list_of_list])))
cols = max(map(len, list_of_list))
output = '+'+('-'*(number_width+2)+'+')*cols + '\n'
for row in list_of_list:
for column in row:
output += '|' + ' {:^{width}d} '.format(column, width = number_width)
output+='|\n+'+('-'*(number_width+2)+'+')*cols + '\n'
return output
这应该行，列和数量的可变数量的工作的数字（数字）
data = [[1,2,30],
[4,23125,6],
[7,8,999],
]
print print_matrix(data)
>>>>+-------+-------+-------+
| 1 | 2 | 30 |
+-------+-------+-------+
| 4 | 23125 | 6 |
+-------+-------+-------+
| 7 | 8 | 999 |
+-------+-------+-------+
tabletext适应这口井
import tabletext
data = [[1,2,30],
[4,23125,6],
[7,8,999],
]
print tabletext.to_text(data)
结果：
┌───┬───────┬─────┐
│ 1 │ 2 │ 30 │
├───┼───────┼─────┤
│ 4 │ 23125 │ 6 │
├───┼───────┼─────┤
│ 7 │ 8 │ 999 │
└───┴───────┴─────┘
我刚刚发现tabulate有一个HTML选项，使用起来相当简单。
神似韦恩沃纳的回答是：
from IPython.display import HTML, display
import tabulate
table = [["Sun",696000,1989100000],
["Earth",6371,5973.6],
["Moon",1737,73.5],
["Mars",3390,641.85]]
display(HTML(tabulate.tabulate(table, tablefmt='html')))
还在寻找一些简单的使用，以创建更复杂的表格布局像乳胶语法和格式合并单元格，并在笔记本上做变量代换：
Allow references to Python variables in Markdown cells #2958
用于将任何python数据结构（字符串和列表嵌套在一起）呈现为HTML的通用函数集。
from IPython.display import HTML, display
def _render_list_html(l):
o = []
for e in l:
o.append('<li>%s</li>' % _render_as_html(e))
return '<ol>%s</ol>' % ''.join(o)
def _render_dict_html(d):
o = []
for k, v in d.items():
o.append('<tr><td>%s</td><td>%s</td></tr>' % (str(k), _render_as_html(v)))
return '<table>%s</table>' % ''.join(o)
def _render_as_html(e):
o = []
if isinstance(e, list):
o.append(_render_list_html(e))
elif isinstance(e, dict):
o.append(_render_dict_html(e))
else:
o.append(str(e))
return '<html><body>%s</body></html>' % ''.join(o)
def render_as_html(e):
display(HTML(_render_as_html(e)))
我曾经有过同样的问题。我找不到任何可以帮助我的东西，所以我最终编写了类PrintTable - 代码如下。还有一个输出。使用很简单：
ptobj = PrintTable(yourdata, column_captions, column_widths, text_aligns)
ptobj.print()
或在一行：
PrintTable(yourdata, column_captions, column_widths, text_aligns).print()
输出：
-------------------------------------------------------------------------------------------------------------
Name | Column 1 | Column 2 | Column 3 | Column 4 | Column 5
-------------------------------------------------------------------------------------------------------------
Very long name 0 | 0 | 0 | 0 | 0 | 0
Very long name 1 | 1 | 2 | 3 | 4 | 5
Very long name 2 | 2 | 4 | 6 | 8 | 10
Very long name 3 | 3 | 6 | 9 | 12 | 15
Very long name 4 | 4 | 8 | 12 | 16 | 20
Very long name 5 | 5 | 10 | 15 | 20 | 25
Very long name 6 | 6 | 12 | 18 | 24 | 30
Very long name 7 | 7 | 14 | 21 | 28 | 35
Very long name 8 | 8 | 16 | 24 | 32 | 40
Very long name 9 | 9 | 18 | 27 | 36 | 45
Very long name 10 | 10 | 20 | 30 | 40 | 50
Very long name 11 | 11 | 22 | 33 | 44 | 55
Very long name 12 | 12 | 24 | 36 | 48 | 60
Very long name 13 | 13 | 26 | 39 | 52 | 65
Very long name 14 | 14 | 28 | 42 | 56 | 70
Very long name 15 | 15 | 30 | 45 | 60 | 75
Very long name 16 | 16 | 32 | 48 | 64 | 80
Very long name 17 | 17 | 34 | 51 | 68 | 85
Very long name 18 | 18 | 36 | 54 | 72 | 90
Very long name 19 | 19 | 38 | 57 | 76 | 95
-------------------------------------------------------------------------------------------------------------
为类PrintTable
# -*- coding: utf-8 -*-
# Class
class PrintTable:
def __init__(self, values, captions, widths, aligns):
if not all([len(values[0]) == len(x) for x in [captions, widths, aligns]]):
raise Exception()
self._tablewidth = sum(widths) + 3*(len(captions)-1) + 4
self._values = values
self._captions = captions
self._widths = widths
self._aligns = aligns
def print(self):
self._printTable()
def _printTable(self):
formattext_head = ""
formattext_cell = ""
for i,v in enumerate(self._widths):
formattext_head += "{" + str(i) + ":<" + str(v) + "} | "
formattext_cell += "{" + str(i) + ":" + self._aligns[i] + str(v) + "} | "
formattext_head = formattext_head[:-3]
formattext_head = " " + formattext_head.strip() + " "
formattext_cell = formattext_cell[:-3]
formattext_cell = " " + formattext_cell.strip() + " "
print("-"*self._tablewidth)
print(formattext_head.format(*self._captions))
print("-"*self._tablewidth)
for w in self._values:
print(formattext_cell.format(*w))
print("-"*self._tablewidth)
示范
的代码# Demonstration
headername = ["Column {}".format(x) for x in range(6)]
headername[0] = "Name"
data = [["Very long name {}".format(x), x, x*2, x*3, x*4, x*5] for x in range(20)]
PrintTable(data, \
headername, \
[70, 10, 10, 10, 10, 10], \
["<",">",">",">",">",">"]).print()
在这里，我写了Python的抽象。代码不麻烦。 :)
欲输出，其中每列具有最小可能宽度， 其中列与白色空间填充（但这是可以改变的）和行由换行分隔的表（但是这可以更改）以及使用str（但是...）格式化每个项目的位置。
def ftable(tbl, pad=' ', sep='\n', normalize=str):
# normalize the content to the most useful data type
strtbl = [[normalize(it) for it in row] for row in tbl]
# next, for each column we compute the maximum width needed
w = [0 for _ in tbl[0]]
for row in strtbl:
for ncol, it in enumerate(row):
w[ncol] = max(w[ncol], len(it))
# a string is built iterating on the rows and the items of `strtbl`:
# items are prepended white space to an uniform column width
# formatted items are `join`ed using `pad` (by default " ")
# eventually we join the rows using newlines and return
return sep.join(pad.join(' '*(wid-len(it))+it for wid, it in zip(w, row))
for row in strtbl)
函数签名，ftable(tbl, pad=' ', sep='\n', normalize=str)，其默认参数旨在 提供最大的灵活性。
您可以自定义
pad='&', sep='\\\\\n'有散装乳胶表）str，但如果 你知道，所有的数据是浮点lambda item: "%.4f"%item可能是一个合理的选择，等浅表性测试：
我需要一些测试数据，可能涉及不同的宽度 列，这样的算法需要一点更复杂（但只是一点点;）
In [1]: from random import randrange
In [2]: table = [[randrange(10**randrange(10)) for i in range(5)] for j in range(3)]
In [3]: table
Out[3]:
[[974413992, 510, 0, 3114, 1],
[863242961, 0, 94924, 782, 34],
[1060993, 62, 26076, 75832, 833174]]
In [4]: print(ftable(table))
974413992 510 0 3114 1
863242961 0 94924 782 34
1060993 62 26076 75832 833174
In [5]: print(ftable(table, pad='|'))
974413992|510| 0| 3114| 1
863242961| 0|94924| 782| 34
1060993| 62|26076|75832|833174
你想只使用'print'的功能呢？数字的宽度是固定的（1位数，3位数？ – tglaria