使用C＃将图像转换为灰度使用C＃

Question

嗨，大家我想将所有图像转换为我的目录中的灰度，但是我知道的代码只能一个接一个地完成这个任务!!但是我有很多图像，而且我希望如果有该转换所有图像目录代码为灰度或

Answer 1

假设你有一个名为path变量，它是处理图像的文件夹的路径，并假设您可以使用WPF的API，将图像转换：

DirectoryInfo dirInfo = new DirectoryInfo(path); 

foreach (FileInfo fileInfo in dirInfo.EnumerateFile()) { 
    ProcessImage(FileInfo.FullName); 
} 

void ProcessImage(string image) { 
    byte[] imageData = null; 

    try { 
     // Load the data in the file into a byte array for processing. 
     imageData = File.ReadAllBytes(image); 

    } catch (Exception) { 
     // Your error handling code here 
    } 

    // We're going to put the image into this object 
    BitmapImage src = new BitmapImage(); 

    try { 
     // Load the image into a memory stream, then into src. 
     using(MemoryStream stream = new MemoryStream(imageData)) { 
      src.BeginInit(); 
      src.CacheOption = BitmapCacheOption.OnLoad; // Causes the bitmap data to be loaded now, not at a later time. 
      src.StreamSource = stream; 
      src.EndInit(); 
     } 
    } catch (NotSupportedException) { 
     // The bitmap format is not supported. Your error handler here. 
    } 

    try { 
     // Create a FormatConvertedBitmap object & set it up. 
     FormatConvertedBitmap dst = new FormatConvertedBitmap(); 
     dst.BeginInit(); 
     dst.DestinationFormat = PixelFormats.Gray8; // Use whatever gray scale format you need here 
     dst.Source   = src; 

     // Now convert the image to 8 bits per pixel grey scale. 
     dst.EndInit(); 

     // Compute the dst Bitmap's stride (the length of one row of pixels in bytes). 
     int stride = ((dst.PixelWidth * dst.Format.BitsPerPixel + 31)/32) * 4; 

     // Allocate space for the imageBytes array. 
     imageBytes = new byte[ stride * dst.PixelHeight ]; 

     // Get the pixels out of the dst image and put them into imageBytes. 
     dst.CopyPixels(Int32Rect.Empty, imageBytes, stride, 0); 

    } catch (Exception ex) { 
     // Your error handler here. 
    } 

    // Any other code to save or do something else with the image. 
}