我试图创建一个OOP友好的Java二十一点游戏的进展我的知识。OOP二十一点游戏(创建甲板)
我碰了壁,我只是不知道不够看的问题。想知道是否有人能指出我的问题。
此外,谷歌搜索关于这个话题的相关后,我发现人们一次又一次的说用枚举会更有利,因为初学者会这样建议?或者我应该暂时坚持使用字符串数组。
谢谢。
我的代码:
public class BlackJack{
BlackJack() {
Deck deck = new Deck();
deck.createDeck();
System.out.println(deck.deckList);
}
public static void main(String[] args) {
new BlackJack();
}
}
public class Card{
private String valueCard;
private String suitCard;
public Card(String value, String suit) {
this.valueCard = value;
this.suitCard = suit;
}
public String getValue() {
return valueCard;
}
public String getSuit() {
return suitCard;
}
}
import java.util.ArrayList;
public class Deck {
ArrayList<Card> deckList = new ArrayList<Card>();
String[] value = {"Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten",
"Jack", "Queen", "King", "Ace"};
String[] suit = {"Hearts", "Clubs", "Spades", "Diamonds"};
Deck() {
deckList = new ArrayList<Card>();
}
public void createDeck() {
for (int i = 0; i < value.length; i++) {
for (int x = 0; x < suit.length; x++) {
Card card = new Card(value[i], suit[x]);
deckList.add(card);
}
}
}
}
编辑:此刻我出把从我的println是: [卡@ addbf1,卡@ 42e816,卡@ 9304b1,......等] 什么这个意思?
谢谢你的时间。
编辑:任何人谁也需要一个答案,这在未来:
补充说:
@Override
public String toString(){
return valueCard + " of " + suitCard;
}
}
到我的卡类,然后在甲板类中使用它:
import java.util.ArrayList;
public class Deck {
ArrayList<Card> deckList = new ArrayList<Card>();
String[] value = {"Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten",
"Jack", "Queen", "King", "Ace"};
String[] suit = {"Hearts", "Clubs", "Spades", "Diamonds"};
Deck() {
deckList = new ArrayList<Card>();
}
public void createDeck() {
for (int i = 0; i < value.length; i++) {
for (int x = 0; x < suit.length; x++) {
Card card = new Card(value[i], suit[x]);
deckList.add(card);
card.toString();
}
}
}
}
ENUM: 公开课CardEnum {
public enum Rank { DEUCE, THREE, FOUR, FIVE, SIX,
SEVEN, EIGHT, NINE, TEN, JACK, QUEEN, KING, ACE }
public enum Suit { CLUBS, DIAMONDS, HEARTS, SPADES }
}
public class Card{
private CardEnum.Rank rank;
private CardEnum.Suit suit;
public Card(CardEnum.Rank rank, CardEnum.Suit suit) {
this.rank = rank;
this.suit = suit;
}
public Rank getRank() {
return rank;
}
public Suit getSuit() {
return suit;
}
@Override
public String toString(){
return rank + " of " + suit;
}
}
如果你的目标是更多的“面向对象”,你应该考虑把你的卡片打包成枚举。查看卡片组示例的http://docs.oracle.com/javase/1.5.0/docs/guide/language/enums.html – assylias
@assylias感谢您的链接,很棒的信息!现在实现枚举。谢谢。 – speak