if(isset($_POST['submit'])) {
$doc = new Doc_Schedule();
$doc->doctor = $_POST['doctor'];
$doc->department = $_POST['dpt'];
$doc->sheduledate = $_POST['date'];
$doc->scheduletime = $_POST['time'];
if($doc->create()) {
$message = "Doctors Information Saved Successfully";
} else {
$message = join("<br/>",$doc->errors);
}
}
<select name="doctor" id="Deptmentselectbox" class="AllSelectBoxes">
<option value="">Select Doctor</option>
<?php
$sql = "SELECT `fullname`,`depid`,`docid` FROM `doctors` ORDER BY fullname ASC";
$result = $database->query($sql) or die('cannot connect to the database');
while($row = mysql_fetch_array($result)) {
echo"<option value= ".$row['docid'].">".$row['fullname']."</option>";
}
?>
</select>
发送两个ID我有一个选择框,它会告诉我在一个表中的医生。当我点击某个医生时,我想将doctors.docid
和doctors.deptid(department id)
发送给一个班级进行进一步处理。通过选择框
我很难找到一个解决方案,其他丹创建一个新的部门ID选择框。
迄今提出的所有解决方案应该为你工作 – 2013-03-09 20:59:49
请考虑接受一个答案(点击左侧刻度),如果它实际上回答了你的问题 – michi 2013-04-14 12:50:12