我目前正在我的高中的计算机科学课上,并正在编写一个程序来模拟康威的生命游戏。我正在使用JavaScript的Code Studio“App Lab”中编写程序,这是我们一直在学习的东西。它在您设计的左侧有一个智能手机。程序没有进入for循环
到目前为止,它已经很好用了,但我正在尝试在屏幕上绘制单元格,并且我的程序拒绝进入将绘制单元格(用按钮表示)的for循环。绘制CellBoard的函数称为drawBoard,是CellBoard对象内的一种方法。
function Cell(x, y, id) {
//base unit for the program, can be either dead or alive based on Conway's
//Game of Life Rules
this.xPos = x;
this.yPos = y;
this.id = "cell" + id;
this.alive = false;
this.aliveNextTurn = false;
this.aliveNeighbors = 0;
this.age = 0;
this.swapState = function(){
if(this.alive){
this.alive = false;
}
else{
this.alive = true;
}
};
}
function CellBoard(width, height){
//the board of cells, this object will house all the methods for the rule
//checking and state setting
this.board = [];
var count = 0;
for(var x = 0; x<width; x++){
var boardY =[];
for(var y = 0; y<height; y++){
boardY.push(new Cell(x,y,count));
count++;
}
this.board.push(boardY);
}
this.drawBoard = function(){
//draws the board of cells on the screen as buttons so that the user can
//initially set them
setScreen("simulationScreen");
//console.log("screen set");
//console.log("starting button making");
for(var i = 0; i<this.width; i++){ //<----the problem is here
//console.log("starting loop");
for(var j = 0; j<this.height; j++){
//console.log("making button");
button(this.board[i][j].id, "test");
setPosition(this.board[i][j].id, 20+(280/i), 20+(280/j), 280/i, 280/j);
setProperty(this.board[i][j].id, "background-color", rgb(0,0,0)); //black background by default
//console.log(getProperty(this.board[i][j].id, "x"));
}
}
//console.log("done drawing board");
};
}
var testBoard = new CellBoard(3, 3);
testBoard.drawBoard();
任何帮助,非常感谢,谢谢!
下面是有问题的功能控制台日志:
screen set
starting button making
done drawing board
如果你在我们的代码中投掷并抱怨,“它不起作用!”你很可能会受到不好的待遇。您应该阅读常见问题解答,了解如何提出正确问题的建议。 –
如果你正在调用cellBoard,它必须进入for循环,你只是没有得到你期望的结果。你看过控制台输出吗?您可以添加一些控制台日志记录来查明事情正在破裂的地方。 – Difster
@Difster它进入函数,然后更改屏幕,但只是跳过for循环,我会添加调试解除控制台日志。 – Jamerack