Python登录脚本

我知道类似的问题已经被问到，我已经阅读过。我还阅读了我能找到的大多数其他相关文章。我已经尝试httplib2，标题修改，以及任何我可以找到或想到的，但我无法获得此登录脚本工作。Python登录脚本

import cookielib 
import urllib 
import urllib2 

cj = cookielib.CookieJar() 
opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) 
resp = opener.open('http://www.biocidecity.com') 

theurl = 'http://www.biocidecity.com/index.php' 
body={'username':'someusername','password':'somepassword', 'login' : '1'} 
txdata = urllib.urlencode(body) txheaders = {'User-agent' : 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'} 


try: 
    req = urllib2.Request(theurl, txdata, txheaders) 
    handle = opener.open(req) 
    HTMLSource = handle.read() 
    f = file('test.html', 'w') 
    f.write(HTMLSource) 
    f.close() 

except IOError, e: 
    print 'We failed to open "%s".' % theurl 
    if hasattr(e, 'code'): 
     print 'We failed with error code - %s.' % e.code 
    elif hasattr(e, 'reason'): 
     print "The error object has the following 'reason' attribute :", e.reason 
     print "This usually means the server doesn't exist, is down, or we don't have an internet connection." 
     sys.exit() 

else: 
    print 'Here are the headers of the page :' 
    print handle.info()

首先，这不是我的脚本，但我修改了一些。其次，我认为这与cookie的处理方式有关，但我无法弄清楚。我也替换了用户名密码组合。

来源

2010-12-01 John

“我不能让这个登录脚本的工作”。你也许应该定义**正在做什么以及为什么你不喜欢那样做。它是否有语法错误？它是否从Web服务器返回401错误？你看到了什么结果？ – 2010-12-01 17:53:42

我想它再次服务的期限，但你应该尝试

import cookielib 
import urllib 
import urllib2 

cj = cookielib.CookieJar() 
opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) 
resp = opener.open('http://www.biocidecity.com') 

theurl = 'http://www.biocidecity.com/index.php' 
body={'username':'someusername','password':'somepassword', 'login' : '1'} 
txdata = urllib.urlencode(body) txheaders = {'Referer': 'http://www.biocidecity.com/index.php'} 


try: 
    req = urllib2.Request(theurl, txdata, txheaders) 
    handle = opener.open(req) 
    HTMLSource = handle.read() 
    f = file('test.html', 'w') 
    f.write(HTMLSource) 
    f.close() 

except IOError, e: 
    print 'We failed to open "%s".' % theurl 
    if hasattr(e, 'code'): 
     print 'We failed with error code - %s.' % e.code 
    elif hasattr(e, 'reason'): 
     print "The error object has the following 'reason' attribute :", e.reason 
     print "This usually means the server doesn't exist, is down, or we don't have an internet connection." 
     sys.exit() 

else: 
    print 'Here are the headers of the page :' 
    print handle.info()

来源

2010-12-01 19:40:09

Python登录脚本

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