为什么这个Ragel文件会产生隐式转换错误？ （Ragel与d）

Question

我有以下的（很简单）Ragel文件scanner.rl：使用ragel -D scanner.rl

void lex(string data) { 
    int cs, act, top; 
    auto p = data.ptr; 
    typeof(p) 
     pe = &data[$ -1], 
     eof = pe, 
     ts, 
     te; 

    %%{ 
     machine scanner; 

     identifier = alpha . alnum**; 

     main := |* 
      identifier => { ("Identifier: " + data[ts..te]).writeln; }; 
      space; 
     *|; 

     write data; 
     write init; 
     write exec; 
    }%% 
} 

void main() { 
    "this is a test".lex; 
} 

我转换scanner.rl到scanner.d。当我尝试编译生成的文件D与dmd scanner.d，我收到以下错误信息：

scanner.d(97): Error: cannot implicitly convert expression (&_scanner_actions[cast(ulong)_scanner_from_state_actions[cast(ulong)cs]]) of type const(byte)* to byte* scanner.d(110): Error: cannot implicitly convert expression (&_scanner_trans_keys[cast(ulong)_scanner_key_offsets[cast(ulong)cs]]) of type const(char)* to char* scanner.d(166): Error: cannot implicitly convert expression (&_scanner_actions[cast(ulong)_scanner_trans_actions[cast(ulong)_trans]]) of type const(byte)* to byte* scanner.rl(22): Error: cannot implicitly convert expression (ts) of type immutable(char)* to ulong scanner.d(186): Error: cannot implicitly convert expression (&_scanner_actions[cast(ulong)_scanner_to_state_actions[cast(ulong)cs]]) of type const(byte)* to byte*

也许我失去了一些重要的东西？

Answer 1

你确定ragel正在生成D2代码吗？看起来它缺少const ....看着ragel的源代码，看起来像ragel -D生成D1和ragel -E生成D2，虽然这在--help中没有记录！