2016-10-19 119 views
0

我想绑定一个python类(从BoxLayout小部件inheres)的属性,以及该类的kv配置文件。Kivy Python - 传递参数并绑定kv和python文件

我想要做的是将一些值传递给类,并在kv文件TextInput id(这是该类的kv描述)旁边打印该值。当我跑我的代码时,我得到一个错误:

TypeError: addBoxClass() missing 1 required positional argument: 'someNumber' 

我认为我过于复杂的事情,因为这应该是相当简单的。 我的一些代码位,我希望它是明确的:

#at some point in my main code I call SomeClass  
box=SomeClass() 
box.add_widget(SomeClass.addBoxClass(someNumber)) #someNumber is a value that I want to print in def printInput, next to the kv file's TextInput id. 

#then this is the class 
class SomeClass(BoxLayout): 
def __init__(self, **kwargs): 
    super(NumOfRoomsClass, self).__init__(**kwargs) 
    self.number = None 

def addBoxClass(self,someNumber):   
    self.number = someNumber #This is where I get my error 
    #create and rern a label 
    boxLabel = BoxLayout()   
    Lab = Label(text= self.number) 
    boxLabel.add_widget(Lab) 
    return (boxLabel) 

def printInput(self, text): 
    input= int(text) 
    print ("self.number = ", self.number , "input = ",input) #This is what I'm aftre 

,并在我的.kv文件I`ve得到这个:

<SomeClass>: 
    Label: 
     text: "Number of rooms" 

    TextInput: 
     multiline: False 
     id: inputId 
     on_text_validate: root.printInput(inputId.text) 

回答

0

当我看着你的代码,我没有看到你在哪里调用了addBoxClass()函数。

您创建了SomeClass的一个实例。其中:

self.number = None 

如果您验证了您的textInput,它将调用printInput。 addBoxClass()不被调用。

0

看起来像someNumber,你试图从你的python文件调用尚未定义。

#at some point in my main code I call SomeClass  
box=SomeClass() 
box.add_widget(SomeClass.addBoxClass(someNumber)) #someNumber is a value that I want to print in def printInput, next to the kv file's TextInput id. 

应该

#at some point in my main code I call SomeClass 
someNumber = 1 
box=SomeClass() 
box.add_widget(SomeClass.addBoxClass(someNumber)) #someNumber is a value that I want to print in def printInput, next to the kv file's TextInput id. 

someNumber必须给出一个值,你用它