如何反序列化这个JSON对象？

Question

import simplejson 
from urllib2 import urlopen 
from simplejson import loads 
from django.core import serializers 
content = loads(urlopen('https://graph.facebook.com/1234676502/feed').read()) 
content = simplejson.dumps(content,sort_keys=True, indent=4) 
print content 
json_serializer = serializers.get_serializer("json")() 
json_serializer.deserialize(content) 

在运行上面的Python代码即时得到以下错误：

Traceback (most recent call last): 
    File "/var/www/youedo/test.py", line 22, in <module> 
    json_serializer = serializers.get_serializer("json")() 
    File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/__init__.py", line 63, in get_serializer 
    _load_serializers() 
    File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/__init__.py", line 109, in _load_serializers 
    register_serializer(format, BUILTIN_SERIALIZERS[format], serializers) 
    File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/__init__.py", line 51, in register_serializer 
    module = importlib.import_module(serializer_module) 
    File "/usr/local/lib/python2.6/dist-packages/django/utils/importlib.py", line 35, in import_module 
    __import__(name) 
    File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/xml_serializer.py", line 6, in <module> 
    from django.core.serializers import base 
    File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/base.py", line 7, in <module> 
    from django.db import models 
    File "/usr/local/lib/python2.6/dist-packages/django/db/__init__.py", line 14, in <module> 
    if not settings.DATABASES: 
    File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 276, in __getattr__ 
    self._setup() 
    File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 38, in _setup 
    raise ImportError("Settings cannot be imported, because environment variable %s is undefined." % ENVIRONMENT_VARIABLE) 
ImportError: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined. 

...当我打印的内容是正确打印JSON字符串。

编辑：2 进口simplejson 从进口的urllib2的urlopen 从simplejson进口负载 从django.core进口串行 含量=负载（的urlopen（'https://graph.facebook.com/1234676502/feed “）.read（））

json_serializer = serializers.get_serializer("json")() 
json_serializer.get_deserialize(content) 

我把这个代码在我view.py然后我得到了以下错误：

AttributeError at /rss 

'Serializer' object has no attribute 'get_deserialize' 

Request Method:  GET 
Request URL: http://127.0.0.1:8000/rss 
Django Version:  1.2.4 
Exception Type:  AttributeError 
Exception Value:  

'Serializer' object has no attribute 'get_deserialize' 

Answer 1

你的错误与json本身没有任何关系，它明确指出它不能导入DJANGO_SETTINGS这意味着你没有django app context。最简单的方法是安装django扩展程序，它提供了命令./manage.py runscript，它用django应用程序上下文运行脚本。

Django extensions can be found here

编辑：：看你的第二个编辑，我可以看到你正在使用的方法get_deserialize()，正确的方法应该是deserialize()，据我所知。