2
我需要打开文件夹中的所有Excel文件,并将每个文件的第57,77,73,77行复制到同一个工作簿中。复制文件夹中所有文件的数据
这这是我到目前为止有:
Dim i As Integer
Dim wbOpen As Workbook
Dim MyPath As String
Dim strFilename As String
MyPath = "C:\foldername" 'the folder
strFilename = Dir(MyPath & "\*.xls") 'all excel files in folder
Do Until strFilename = ""
'here it gives an error, saying it can't open file,
' even though it apparently has found it
wbOpen = Workbooks.Open(strFilename)
'copy relevant text
Workbooks(2).Activate
Sheets("blad1").Rows(1, 57, 72, 73, 74).Copy
Workbooks(1).Activate
'select the first empty row
irow = ActiveSheet.UsedRange.Rows.Count + 1
'insert the copied
irow.Insert Shift:=xlDown
'close the workbook without saving
Workbooks(2).Close SaveChanges:=False
Close
Loop
不,仍然没有工作。奇怪的是,它一直给出这个错误:“(正确的文件名.xls)找不到。”线路Workbooks.Open(strFilename) – Seeb
好了,我已经试过如下: strFilename = DIR() Workbooks.Open(mypath中& “\” &strFilename) 的休息是相同 从而打开第一个文件,但后来说该文件不是真正的xls文件,并停止.. – Seeb
我收到与以前一样的错误。问题可能是,当我尝试手动打开工作簿时,我也得到相同的msg:“文件没有与其扩展名相同的文件格式。也许它来自不可靠的来源blabla,您确定要打开它吗?” – Seeb