如何在C中的char数组中搜索字符串？

Question

比如我有：

char buff[1000]; 

我想如果搜索字符串“hassasin”是在字符数组。这是我尝试过的。

char word[8] = "hassasin"; 
char Buffer[1000]=sdfhksfhkasd/./.fjka(hassasin)hdkjfakjsdfhkksjdfhkjh....etc 
int k=0; 
int t=0; 
int len=0; 
int sor=0; 
for (k=0; k<1000; k++){ 
    for (t=0; t<8; t++){ 
     if (Buffer[k]==word[t]) len++; 
     if (len==8) "it founds 0.9.1" 
    } 
} 

Answer 1

如果chararray包含stringend或不以\ 0结束了，你可以使用这些代码，因为的strstr都会对这些的刹车：

#include <stdio.h> 
int main() 
{ 
    char c_to_search[5] = "asdf"; 

    char text[68] = "hello my name is \0 there is some other string behind it \n\0 asdf"; 

    int pos_search = 0; 
    int pos_text = 0; 
    int len_search = 4; 
    int len_text = 67; 
    for (pos_text = 0; pos_text < len_text - len_search;++pos_text) 
    { 
     if(text[pos_text] == c_to_search[pos_search]) 
     { 
      ++pos_search; 
      if(pos_search == len_search) 
      { 
       // match 
       printf("match from %d to %d\n",pos_text-len_search,pos_text); 
       return; 
      } 
     } 
     else 
     { 
      pos_text -=pos_search; 
      pos_search = 0; 
     } 
    } 
    // no match 
    printf("no match\n"); 
    return 0; 
} 

http://ideone.com/2In3mr

Answer 2

是的，你可以只使用strstr此：

#include <stdlib.h> 
#include <string.h> 

char buff[1000]; 
char *s; 

s = strstr(buff, "hassasin");  // search for string "hassasin" in buff 
if (s != NULL)      // if successful then s now points at "hassasin" 
{ 
    printf("Found string at index = %d\n", s - buff); 
}         // index of "hassasin" in buff can be found by pointer subtraction 
else 
{ 
    printf("String not found\n"); // `strstr` returns NULL if search string not found 
}