2017-05-22 27 views
-1

这是我的一些操作后的回应。基于empid,我想分组区,产品,并获得短信和WhatsApp的数量。如何在JavaScript中对一些常用属性进行分组?

[ 
    { 
    "_id": { 
     "empid": "sindhu", 
     "district": "Hyderabad", 
     "product": "Fair Fertilizers" 
    }, 
    "sms": 1 
    }, 
    { 
    "_id": { 
     "empid": "nagaraju", 
     "district": "Guntur", 
     "product": "Fair Fertilizers" 
    }, 
    "sms": 2 
    }, 
    { 
    "_id": { 
     "empid": "sindhu", 
     "district": "Hyderabad", 
     "product": "Fair Fertilizers" 
    }, 
    "whatsapp": 2 
    }, 
    { 
    "_id": { 
     "empid": "sindhu", 
     "district": "Krishna", 
     "product": "Fair Fertilizers" 
    }, 
    "whatsapp": 2 
    } 
] 

我希望上述格式的数据如下所示。

[ 
    { 
    "sindhu":[ 
     { 
      "district": "Hyderabad", 
      "product": "Fair Fertilizers", 
      "sms": 1, 
      "whatsapp": 2 
     }, 
     { 
      "district": "Krishna", 
      "product": "Fair Fertilizers", 
      "whatsapp": 2 
     }, 
    ] 
    }, 
    { 
    "nagaraju" : [ 
     { 
      "district": "Guntur", 
      "product": "Fair Fertilizers", 
      "sms": 2 
     } 
    ] 
    } 
] 

为了得到这样的结果,我尝试了下面的代码。但我没有明白。

var groups = Object.create(null); 
for (var i = 0; i < allTools.length; i++) { 
    var item = allTools[i]; 
    if(!groups[item._id]) { 
     groups[item._id] = []; 
    } 
    groups[item._id].push({ 
     district: item.district, 
     product: item.product, 
     sms: item.sms, 
     whatsapp: item.whatsapp, 
     mailing: item.mailing, 
     telecalling: item.telecalling, 
     enquiry: item.enquiry 
    }); 
} 
var data = []; 
for (var x in groups) { 
    var obj = {}; 
    obj[x] = groups[x]; 
    data.push(obj); 
} 
+4

的可能的复制[什么是GROUPBY对象的JavaScript的阵列上的最有效的方法?(https://stackoverflow.com/questions/14446511/what-is-the最有效的方法,在一个对象上的一个javascript对象数组) – Rajesh

+1

请分享一些想法和你已经尝试过。 –

+0

@NinaScholz,我编辑了这个问题。请考虑一下。 –

回答

1

您可以使用迭代嵌套方法通过使用哈希表来构建对结果数组的必要引用,该哈希表可用于使用键以及保留部分结果。

由于empiddistrict的分组键的每个级别的不同需要,更大的简化是不可能的。

var data = [{ _id: { empid: "sindhu", district: "Hyderabad", product: "Fair Fertilizers" }, sms: 1 }, { _id: { empid: "nagaraju", district: "Guntur", product: "Fair Fertilizers" }, sms: 2 }, { _id: { empid: "sindhu", district: "Hyderabad", product: "Fair Fertilizers" }, whatsapp: 2 }, { _id: { empid: "sindhu", district: "Krishna", product: "Fair Fertilizers" }, whatsapp: 2 }], 
 
    values = ['sms', 'whatsapp'], 
 
    result = [], 
 
    hash = { _: result }; 
 

 
data.forEach(function (o) { 
 
    var temp = {}, 
 
     reference = hash; 
 

 
    if (!reference[o._id.empid]) { 
 
     reference[o._id.empid] = { _: [] }; 
 
     temp[o._id.empid] = reference[o._id.empid]._; 
 
     reference._.push(temp); 
 
    } 
 
    reference = reference[o._id.empid]; 
 

 
    if (!reference[o._id.district]) { 
 
     reference[o._id.district] = { district: o._id.district, product: o._id.product }; 
 
     reference._.push(reference[o._id.district]); 
 
    } 
 
    reference = reference[o._id.district]; 
 

 
    values.forEach(function (k) { 
 
     if (k in o) { 
 
      reference[k] = o[k]; 
 
     } 
 
    }); 
 
}); 
 

 
console.log(result); 
 
console.log(hash);
.as-console-wrapper { max-height: 100% !important; top: 0; }

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