1
我想在SDL2和SDL2_gfx库的屏幕上绘制一些图形原语。但不知何故,SDL2_gfx函数似乎不起作用。下面的代码应该绘制白色背景上的简单的绿色填充矩形SDL2_gfx函数不起作用
#include <SDL2/SDL.h>
#include <SDL2/SDL2_gfxPrimitives.h>
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#define SCREENW 1366
#define SCREENH 768
SDL_Window *window = NULL;
SDL_Renderer *renderer = NULL;
bool init_SDL() {
if(SDL_Init(SDL_INIT_VIDEO) < 0) {
printf("SDL could not initialize! SDL Error: %s\n",SDL_GetError());
return false;
}
window = SDL_CreateWindow("SDL_gfx_Test",SDL_WINDOWPOS_UNDEFINED,SDL_WINDOWPOS_UNDEFINED,SCREENW,SCREENH,SDL_WINDOW_SHOWN);
if(window == NULL) {
printf("Window could not be created! SDL Error: %s\n",SDL_GetError());
return false;
}
renderer = SDL_CreateRenderer(window,-1,SDL_RENDERER_ACCELERATED);
if(renderer == NULL) {
printf("Renderer could not be created! SDL Error: %s\n",SDL_GetError());
return false;
}
if(SDL_SetRenderDrawColor(renderer,0xFF,0xFF,0xFF,0xFF) < 0) {
printf("Renderer color could not be set! SDL Error: %s\n",SDL_GetError());
return false;
}
return true;
}
void close_SDL() {
SDL_DestroyRenderer(renderer);
renderer = NULL;
SDL_DestroyWindow(window);
window = NULL;
SDL_Quit();
}
int main(int argc,char *argv[]) {
Sint16 topRightX = 100;
Sint16 topRightY = 100;
Sint16 bottomLeftX = 300;
Sint16 bottomLeftY = 300;
Uint32 green = 0x00FF00FF;
if(!init_SDL()) {
exit(EXIT_FAILURE);
}
SDL_RenderClear(renderer);
if(boxColor(renderer,topRightX,topRightY,bottomLeftX,bottomLeftY,green) < 0) {
printf("Could not draw box to renderer!\n");
exit(EXIT_FAILURE);
}
SDL_RenderPresent(renderer);
SDL_Delay(3000);
close_SDL();
exit(EXIT_SUCCESS);
}
我编写的代码的命令
gcc -g3 -o sdl_gfx_test sdl_gfx_test.c `sdl2-config --cflags --libs` -lSDL2_gfx
在Ubuntu 14.04
目前还没有编译器错误或警告也没有链接器错误。但屏幕上不会出现绿色矩形。由于SDL_RenderClear(),只显示白色背景。我检查了我的代码十几次,但是我发现没有任何缺陷。有没有人有一个想法,为什么boxColor()不做他的工作?