删除数组元素（C＃）

Question

我想删除用户输入索引和值的int数组元素（意味着用下一个数组元素替代数组元素），所以它在做但在输出中它给了我元素两次示例输入数组为：1 2 3 4 5 6，并且用户说要删除3索引处的第3个元素，则输出为：1 2 4 4 5 6什么是解决方案plz.Without using any function or library。

Console.WriteLine("Enter The Length Of Linear Array"); 
int length = Convert.ToInt32(Console.ReadLine()); 
int[] LinearArr = new int[length + 2]; 
Console.WriteLine("Maximum Number Of Inputs : {0}", length); 


for (int i = 1; i < LinearArr.Length - 1; i++) 
{ 
    LinearArr[i] = Convert.ToInt32(Console.ReadLine()); 
} 
Console.WriteLine("What Number You Want To Delete And At What Index"); 
int InsertNum2 = Convert.ToInt32(Console.ReadLine()); 
int k2 = Convert.ToInt32(Console.ReadLine()); 
Console.WriteLine("Number :{0} And Index :{1}",InsertNum2,k2); 

InsertNum2 = LinearArr[k2]; 
for (int i = k2; i < LinearArr.Length-1; i++) 
{ 
    LinearArr[k2] = LinearArr[k2 + 1]; 


} 
length = length - 1; 
for (int i = 1; i < LinearArr.Length-1; i++) 
{ 
    Console.WriteLine(LinearArr[i]); 
} 
//Input :1 2 3 4 5 6 
//output :1 2 4 4 5 6 

Answer 1

你的代码的问题，你在使用k2是：LinearArr[k2] = LinearArr[k2 + 1];，你应该使用i代替。我认为你的做法是不是一个好方法，也许下面的方法将满足您的要求：

Console.WriteLine("Enter The Length Of Linear Array"); 
int length = Convert.ToInt32(Console.ReadLine()); 
int[] LinearArr = new int[length + 2]; 
Console.WriteLine("Maximum Number Of Inputs : {0}", length); 


for (int i = 1; i < LinearArr.Length - 1; i++) 
{ 
    LinearArr[i] = Convert.ToInt32(Console.ReadLine()); 
} 
Console.WriteLine("What Number You Want To Delete And At What Index"); 
int InsertNum2 = Convert.ToInt32(Console.ReadLine()); 
int k2 = Convert.ToInt32(Console.ReadLine()); 
Console.WriteLine("Number :{0} And Index :{1}",InsertNum2,k2); 

//create a new array with length = LinearArray - 1 
int[] newArray = new int[LinearArray.Length - 1]; 
int currentIndex = 0; 

InsertNum2 = LinearArr[k2]; 
for (int i = 0; i < LinearArr.Length; i++) 
{ 
    //if i == index want to delete, ignore 
    if(i != k2) 
    { 
     newArray[currentIndex] = LinearArray[i]; 
     currentIndex++; 
    } 
} 
length = length - 1; 
for (int i = 0; i < newArray.Length-1; i++) 
{ 
    Console.WriteLine(newArray[i]); 
} 

Answer 2

将数组转换为列表，删除元素并将列表转换回数组。

var numList = LinearArr.ToList(); 
numList.Remove(k2); 
LinearArr = numList.ToArray(); 

Answer 3

你不能在运行时从数组中移除一个项目。你最好的选择是将你的数组转换为列表。

 var a = new[] { "A", "B", "C" }.ToList(); 
     a.RemoveAt(1); 
     foreach (var x in a) 
      Console.WriteLine(x); 

如果由于某种原因您不能使用列表而不是数组，那么您可以逐个移动元素并最后调整数组的大小。

 var a = new[] { "A", "B", "C", "D", "E", "F" }; 
     for (var i = 1; i < a.Length - 1; i++) 
      a[i] = a[i + 1]; 
     Array.Resize(ref a, a.Length - 1); 
     foreach (var x in a) 
      Console.WriteLine(x); 

Answer 4

您应该使用索引i，而不是k2

for (int i = k2; i < LinearArr.Length - 1; i++) 
    LinearArr[i] = LinearArr[i + 1]; 
} 

（k2不改变）