bash的换行符替换成引号

Question

我有以下CSV文件：

"test","test2","test 
3 and some other 

data" 
"test4","test5","test6 and some other 


data" 

我想通过字符\n全部更换为新行（Windows或UNIX风格），所以我将获得：

"test","test2","test\n3 and some other\n\ndata" 
"test4","test5","test6 and some other\n\n\ndata" 

我试着awk但没有成功：

cat myFile.csv | awk -F \" -v OFS=\" '{ 
    for (i=0; i<NF; i++) { 
     gsub("\\n", "\\\\n", $i) 
    } 
    print 
}' 

Answer 1

这里有一个方法：

$ awk '!/"$/{sub(/$/,"\\n");printf "%s",$0;next}1' file 
"test","test2","test\n3 and some other\n\ndata" 
"test4","test5","test6 and some other\n\n\ndata" 

Answer 2

做这项工作˚F或者你？两行相同的想法

awk -v RS="\0" '{gsub(/\n/,"\\n");sub(/\\n$/,"");gsub(/"\\n"/,"\"\n\"");}1' file  

或

awk -v RS="\0" -v ORS="" '{gsub(/\n/,"\\n");sub(/\\n$/,"\n");gsub(/"\\n"/,"\"\n\"")}1' file 

与您的数据：

kent$ cat file 
"test","test2","test 
3 and some other 

data" 
"test4","test5","test6 and some other 


data" 

输出：

kent$ awk -v RS="\0" -v ORS="" '{gsub(/\n/,"\\n");sub(/\\n$/,"\n");gsub(/"\\n"/,"\"\n\"")}1' file 
"test","test2","test\n3 and some other\n\ndata" 
"test4","test5","test6 and some other\n\n\ndata" 

Answer 3

这可能会为你工作（GNU SED）：

sed -r ':a;/^("[^"]*",?){3}$/!{$!N;s/\n/\\n/;ta};P;D' file 

或在紧要关头：

sed ':a;/"$/!{$!N;s/\n/\\n/;ta};P;D' file