如何通过steamid获得用户匹配？

Question

通过此链接，您可以从Dota的2 https://api.steampowered.com/IDOTA2Match_205790/GetMatchHistory/v001/?key=*获得所有比赛** * ***

，但如何通过steamid得到一个单用户的比赛吗？

Answer 1

您需要做的第一件事是将STEAM ID转换为PROFILE ID。这可以使用诸如Steam Condenser项目之类的东西来完成，更简单的是蒸汽冷凝器项目中的function。如果你只是使用这个函数，你将不得不修改抛出的异常，因为SteamCondenserException将不存在。如果您有独特的玩家ID，我建议您使用整个蒸汽冷凝器项目并查看此answer。

/** 
* Converts a SteamID as reported by game servers to a 64bit numeric 
* SteamID as used by the Steam Community 
* 
* @param string $steamId The SteamID string as used on servers, like 
* <var>STEAM_0:0:12345</var> 
* @return string The converted 64bit numeric SteamID 
* @throws SteamCondenserException if the SteamID doesn't have the correct 
* format 
*/ 
    public static function convertSteamIdToCommunityId($steamId) { 
     if($steamId == 'STEAM_ID_LAN' || $steamId == 'BOT') { 
      throw new SteamCondenserException("Cannot convert SteamID \"$steamId\" to a community ID."); 
     } 
     if (preg_match('/^STEAM_[0-1]:[0-1]:[0-9]+$/', $steamId)) { 
      $steamId = explode(':', substr($steamId, 8)); 
      $steamId = $steamId[0] + $steamId[1] * 2 + 1197960265728; 
      return '7656' . $steamId; 
     } elseif (preg_match('/^\[U:[0-1]:[0-9]+\]$/', $steamId)) { 
      $steamId = explode(':', substr($steamId, 3, strlen($steamId) - 1)); 
      $steamId = $steamId[0] + $steamId[1] + 1197960265727; 
      return '7656' . $steamId; 
     } else { 
      throw new SteamCondenserException("SteamID \"$steamId\" doesn't have the correct format."); 
     } 
    } 

现在，你有64位ID，您可以通过这个API调用你已经做。它将传递给account_id参数。

在PHP中，你最终会像这样的东西：

$matches = 10; // Return last 10 matches 
$acct = convertSteamIdToCommunityId(STEAMIDYOUARECHECKING); 
$APIKEY = <YOURKEYHERE>; 

$steamurl = "https://api.steampowered.com/IDOTA2Match_570/GetMatchHistory/V001/?key=$APIKEY&account_id=$acct&Matches_Requested=$matches&format=json"; 
$json_object= file_get_contents($steamurl); 
header('Content-Type: application/json'); 
echo $json_object; 

在该段顶部的三个变量您与匹配的数量填写你要回来，蒸汽ID您正在检查您正在使用的API KEY。你的结果将在$json_object中，供你解析。