我有这个代码,但有时它的工作,有时不(写printf(“ERR:%d \ n”,id))。 我在CUDA 4.1下工作,并具有计算能力2.1的GTS450。CUDA代码不起作用,为什么?
可是没有更高的目标代码,荫只是想找到为什么它不工作,因为我的心告诉我,对不对:]
如果你想运行它,也许你需要执行几次,当出现“错误”或更改网格大小时!
PS:here you can download exe file for win64 - you need to have cuda4.1 driver
class MAN
{
public:
int m_id;
int m_use;
__device__
MAN()
{
m_id = -1;
m_use = 0;
}
};
__device__ int* d_ids = NULL;
__device__ int d_last_ids = 0;
__device__ MAN* d_mans = NULL;
__global__ void init()
{
d_mans = new MAN[500]; //note: 500 is more than enough!
d_ids = new int[500];
for(int i=0; i < 500; i++)
d_ids[i] = 0;
}
__device__ int getMAN() //every block get unique number, so at one moment all running blocks has different id
{
while(true)
{
for(int i=0; i < 500; i++)
if(atomicCAS(&(d_mans[i].m_use), 0, 1)==0)
return i;
}
}
__device__ void returnMAN(int id)
{
int s = atomicExch(&(d_mans[id].m_use), 0);
}
__global__ void testIt()
{
if(threadIdx.x==0)
{
int man = getMAN();
int id = d_mans[man].m_id;
if(id == -1) //If It never works with this "id", its creating new
{
id = atomicAdd(&d_last_ids, 2);
d_ids[id] = 10; //set to non-zero
d_mans[man].m_id = id; //save new id for next time
printf("ADD:%d\n", id);
}
if(d_ids[id]==0)
printf("ERR:%d\n", id); //THIS SHOULD NEVER HAPPEN, BUT BECOMES !!!
returnMAN(man);
}
}
int main()
{
init<<<1, 1>>>();
printf("init() err: %d\n", cudaDeviceSynchronize());
testIt<<<20000, 512>>>();
printf("testIt() err: %d\n", cudaDeviceSynchronize());
getchar();
return 0;
}
你是说'init'内核调用失败?什么是您收到的错误信息? – talonmies 2012-02-21 19:32:37
否没有cuda错误。问题在于程序跳转到“printf(”ERR:%d \ n“,id);”线,但这绝不会发生! – Milan 2012-02-21 22:46:51
你试图达到什么目标? (在更高层次上) – harrism 2012-02-22 04:59:58