我有两个插入语句插入数据库中的记录。我已经使用了事务范围,以便在任何语句失败的情况下,没有任何记录被更新。在第二个过程中,插入失败,但它将数据库中的记录插入到第一个语句中。我在代码中缺少什么?交易范围c#
连接字符串
<add name="Transac.Properties.Settings.TransacDbConnectionString" connectionString="Data Source=.\sqlexpress;Initial Catalog=Transac;Integrated Security=True" providerName="System.Data.SqlClient" />
private void button1_Click(object sender, EventArgs e) {
var scopeOptions = new TransactionOptions();
scopeOptions.IsolationLevel = System.Transactions.IsolationLevel.ReadCommitted;
scopeOptions.Timeout = TimeSpan.MaxValue;
using (TransactionScope transactionScope = new TransactionScope(TransactionScopeOption.Required,scopeOptions)) {
try {
cmd = new SqlCommand("SalesSave", con);
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.Add(new SqlParameter("@BillNo", lblBillNo.Text));
cmd.Parameters.Add(new SqlParameter("@CustName", cboCust_Name.Text.ToUpper()));
cmd.Parameters.Add(new SqlParameter("@Mobile", txtMob.Text));
cmd.ExecuteNonQuery();
cmd = new SqlCommand("SubSave", con);
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.Add(new SqlParameter("@SubBillNo", lblBillNo.Text));
cmd.Parameters.Add(new SqlParameter("@ItemName", dataGridView1.Rows[i].Cells[0].Value.ToString().ToUpper()));
cmd.Parameters.Add(new SqlParameter("@Qty", dataGridView1.Rows[i].Cells[1].Value.ToString()));
//cmd.Parameters.Add(new SqlParameter("@Price", dataGridView1.Rows[i].Cells[2].Value.ToString()));
cmd.ExecuteNonQuery();
transactionScope.Complete();
transactionScope.Dispose();
}
catch (Exception e1) {
MessageBox.Show(e1.Message);
}
}
}
存储过程1:
ALTER PROCEDURE [dbo].[SalesSave]
(
@SalesBillNo as varchar(50),
@CustName as varchar(50),
@Mobile as nvarchar(50)
)
AS
begin
insert into Sales(
SalesBillno,
CustName,
Mobile
)
values (
@SalesBillNo,
@CustName,
@Mobile
)
end
存储过程2
ALTER PROCEDURE [dbo].[SubSave]
@SubSalesBillNo as varchar(50),
@ItemName as nvarchar(50),
@Qty as money,
@Price as money
AS
begin
INSERT INTO SubSales
VALUES(
@SubSalesBillNo,
@ItemName,
@Qty,
@Price
)
end
您的消息框是否显示第二个存储过程中的异常? 为什么当你有一个Using块时调用dispose? – Adam47
是的,它显示第二个存储过程中的异常,因为我已经明确地评论了一个参数,所以它会抛出错误,事务将回滚但不是。之前我使用的是交易声明,这就是为什么处置在那里我会删除它 – NoviceToProgramming
真正的问题是:根本使用3个交易的目的是什么?另外:只有一个命令使用转换的目的是什么? –