查询：哪里隐藏='0'

Question

我如何才能使我的搜索表单仅列出其中hidden = '0'; +其余选项的结果？

$stmt = $dbh->prepare(" 
SELECT * 
FROM  users u 
LEFT JOIN menues m 
ON   u.user_id = m.restaurant_id 
WHERE  (restaurant LIKE CONCAT('%', :term, '%')) 
OR   city LIKE CONCAT('%', :term, '%') 
"); 
$stmt->bindParam(":term", $term); 
$stmt->execute(); 

感谢提前:)

Answer 1

嗯，我希望我知道你需要什么：

$stmt = $dbh->prepare(" 
SELECT * 
FROM  users u 
LEFT JOIN menues m 
ON   u.user_id = m.restaurant_id 
WHERE  (((restaurant LIKE CONCAT('%', :term, '%')) 
OR   city LIKE CONCAT('%', :term, '%')) 
AND   hidden = 0) 
"); 
$stmt->bindParam(":term", $term); 
$stmt->execute(); 

Answer 2

难道你们就不能只是添加

AND hidden = '0' 

到年底你WHERE子句，以便您的查询结束

. 
. 
. 
WHERE (restaurant LIKE ... 
OR city LIKE ...) 
AND hidden='0' 

顺便说一下hidden真的是一个基于字符的列吗？如果没有，你应该加入hidden=0（不带单引号）