我环顾四周,无法找到我的问题的答案。 我想从数据库中的一行,但它只是给了我一个公告称:注意:从数据库请求数据时错误地将数组转换为字符串转换
声明:Array对/ XAMPP字符串转换/ ...
这里是我的代码:
$sql6 = mysql_query("SELECT * FROM replies WHERE thread_id = $thread_id");
$numRows = mysql_num_rows($sql6);
$replies = '';
if ($numRows < 1) {
$replies = "There are no replies yet, you can make the first!";
} else {
while ($rows = mysql_fetch_array($sql6)) {
$reply_content = $rows[5];
$reply_username = $rows[7];
$reply_date = $rows[8];
$reply_author_id = [4];
$sql9 = mysql_query("SELECT * FROM users WHERE id = $reply_author_id");
$numRows = mysql_num_rows($sql);
if ($numRows < 1) {
while ($rows = mysql_fetch_array($sql)) {
$reply_user_fn = $rows['first_name'];
$reply_user_ln = $rows['last_name'];
$reply_user_id = $rows['id'];
$reply_user_pp = $rows['profile_pic'];
$reply_user_lvl = $rows['user_level'];
$reply_user_threads = $rows['threads'];
$reply_user_email = $rows['email'];
}
}
}
}
请帮帮我。我对PHP相当陌生,而且我没有看到我做错了什么。
哪行数不错误是指什么? –
是这行是一个错字? '$ reply_author_id = [4];'? – Konsole