我正在学习servlets,我试图创建一个小程序来获得我创建的类的小时。但我有蜜蜂得到一个例外。下面是代码:为什么这个例外Java?
用户
package Business;
public class User {
private String userId;
public User() {
userId = "";
}
public User(String id) {
userId = id;
}
public void setUserId(String id) {
userId = id;
}
public String getUserId() {
return userId;
}
}
小时
package Business;
import java.util.Calendar;
import java.util.GregorianCalendar;
import business.User;
public class Hours {
private User user;
private Calendar cal = new GregorianCalendar();
private int min = 0;
public Hours(User user) {
this.user = user;
min = cal.get(Calendar.MINUTE);
}
public String getMinutes() {
return Integer.toString(min);
}
public User getUser() {
return user;
}
}
CheckUser
package process;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import Business.User;
import Business.Hours;
public class CheckUser extends HttpServlet {
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String userId = request.getParameter("userID");
User user1 = new User(userId);
Hours h1 = new Hours(user1);
String url = "/show.jsp";
request.setAttribute("hours", h1);
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher(url);
dispatcher.forward(request, response);
}
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String userId = request.getParameter("userID");
User user1 = new User(userId);
Hours h1 = new Hours(user1);
String url = "/show.jsp";
request.setAttribute("hours", h1);
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher(url);
dispatcher.forward(request, response);
}
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String userId = request.getParameter("userID");
User user1 = new User(userId);
Hours h1 = new Hours(user1);
String url = "/show.jsp";
request.setAttribute("hours", h1);
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher(url);
dispatcher.forward(request, response);
}
}
指数
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Project</title>
</head>
<body>
<h1>Employees</h1>
<form action="<%=response.encodeURL("CheckUser")%>" method="get">
<input type="submit" value="Diogo">
<input type="hidden" name="userId" value="1">
</form>
</body>
</html>
显示
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
</head>
<body>
<%@ page import="Business.*, process.*" %>
<%
Hours h1 = (Hours) request.getAttribute("hours");
String userId =h1.getUser().getUserId();
%>
<h1><%= userId %></h1>
</body>
</html>
,从完成此请求防止 它异常
类型异常报告
消息
描述服务器遇到一个内部错误()。
例外
了java.lang.RuntimeException:不可编译的源代码 - 错误的构造函数符号类型:process.CheckUser.doGet(CheckUser.java:37) javax.servlet.http.HttpServlet.service(的HttpServlet .java:621) javax.servlet.http.HttpServlet.service(HttpServlet.java:722)note注意根本原因的 完整堆栈跟踪可在Apache Tomcat/7.0.23日志中找到。
这是迄今为止一个堆栈溢出问题,太多的代码。请将您的代码减少到展示此问题所需的最低限度(请参阅http://sscce.org)。 – 2011-12-18 15:02:24
使用Eclipse或其他IDE来检测汇编问题 – 2011-12-18 15:09:29