根据info groff
(5.11节中的字符转换), \.
应该只打印点。但是,这不是看起来发生的事情。 如果我使这个手册页groff中的转义点
.TH x x x x
\.SH foo
我得到呈现为节标题foo
,而不是打印.SH
。
那么,为什么会发生这种情况,以及如何避免在groff中起始行的 点(和撇号)?
根据info groff
(5.11节中的字符转换), \.
应该只打印点。但是,这不是看起来发生的事情。 如果我使这个手册页groff中的转义点
.TH x x x x
\.SH foo
我得到呈现为节标题foo
,而不是打印.SH
。
那么,为什么会发生这种情况,以及如何避免在groff中起始行的 点(和撇号)?
要在行写入使用\[char46]
年初逃脱点:
\[char46]SH foo
打印
.SH foo
这是预期的行为,但应固定在手册页。 Here是一个错误报告。
您可以在下面阅读\\
(缩写) 和\.
(来自信息页)的说明。
-- Escape: \\
[...]
`\\' is a `delayed' backslash; more precisely, it is the default
escape character followed by a backslash, which no longer has
special meaning due to the leading escape character. It is _not_
an escape sequence in the usual sense! In any unknown escape
sequence `\X' the escape character is ignored and X is printed.
But if X is equal to the current escape character, no warning is
emitted.
As a consequence, only at top-level or in a diversion a backslash
glyph is printed; in copy-in mode, it expands to a single
backslash which then combines with the following character to an
escape sequence.
[...]
-- Escape: \.
Similar to `\\', the sequence `\.' isn't a real escape sequence.
As before, a warning message is suppressed if the escape character
is followed by a dot, and the dot itself is printed.
只需预先设置点与零宽度字:
\&. -- this a a dot.
或暂时切换到另一个控制字符:
.cC#
. -- this is a dot.
#cc