我试图在Swift中创建一个Base64字符串。我有一个Base64编码的字符串及其数组对象的例子。我现在的问题是,我不知道如何获得与示例中给出的等价数组。生成一个JSON数组并将其转换为一个Base64字符串
因为我不想在我的XCode项目中乱搞,所以我在操场上做了以下操作。
定的数组:
{"WHERE":{"Class":"%3f","Location":"3b"},"ORDER":["Day ASC","Location DESC"]}
给Base64编码字符串:
eyJXSEVSRSI6eyJDbGFzcyI6IiUzZiIsIkxvY2F0aW9uIjoiM2IifSwiT1JERVIiOlsiRGF5IEFTQyIsIkxvY2F0aW9uIERFU0MiXX0=
首先在下面,我想重现我解码例如串
let str = "eyJXSEVSRSI6eyJDbGFzcyI6IiUzZiIsIkxvY2F0aW9uIjoiM2IifSwiT1JERVIiOlsiRGF5IEFTQyIsIkxvY2F0aW9uIERFU0MiXX0="
let data = NSData(base64EncodedString: str, options: NSDataBase64DecodingOptions(rawValue: 0))
do {
let result = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments)
} catch let error {
print(error)
}
//"result" is ["WHERE": ["Class": "%3f", "Location": "3b"], "ORDER": ["Day ASC", "Location DESC"]]
来自上面的字符串
var array = [String : AnyObject]()
var arrayPartA = [String : String]()
arrayPartA["Class"] = "%3f"
arrayPartA["Location"] = "3b"
array["ORDER"] = ["Day ASC", "Location DESC"]
array["WHERE"] = arrayPartA
array //The playground says that "array" is ["ORDER": ["Day ASC", "Location DESC"], "WHERE": ["Class": "%3f", "Location": "3b"]]
//"ORDER" and "WHERE" are switched but I don't get them to be at the right position
let utf8str2: NSData = String(array).dataUsingEncoding(NSUTF8StringEncoding)!
let encodedStr = utf8str2.base64EncodedStringWithOptions(NSDataBase64EncodingOptions(rawValue: 0))
//Here "encodedStr" is WyJPUkRFUiI6ICgKICAgICJEYXkgQVNDIiwKICAgICJMb2NhdGlvbiBERVNDIgopLCAiV0hFUkUiOiB7CiAgICBDbGFzcyA9ICIlM2YiOwogICAgTG9jYXRpb24gPSAzYjsKfV0=
//but it should be eyJXSEVSRSI6eyJDbGFzcyI6IiUzZiIsIkxvY2F0aW9uIjoiM2IifSwiT1JERVIiOlsiRGF5IEFTQyIsIkxvY2F0aW9uIERFU0MiXX0=
如果有人能向我解释我做错了什么以及如何重现给定的Base64字符串,我会很高兴。
因为我是这个网站的新手,我提前为错误的布局或其他可能的约定道歉,我不知道。