2016-07-06 16 views
2

我想从一堆本地html文件抓取原始html。我从这个职位的一些帮助获取原始文件阅读:如何从Python中的本地文件抓取某个XPath内的原始所有原始html

Get all text inside a tag lxml

但我的代码目前生产的整个文件,而不是一个子集。现在我似乎错过了一条线,我可以选择一个我想抓取的xpath。

这里是我目前拥有的代码:

def stringify_children(node): 
    from lxml.etree import tostring 
    from itertools import chain 
    parts = ([node.text] + 
      list(chain(*([c.text, tostring(c), c.tail] for c 
      in node.getchildren()))) + 
      [node.tail]) 
    # filter removes possible Nones in texts and tails 
    return ''.join(filter(None, parts)) 

for filename in os.listdir('../news/article/'): 
    if (filename.endswith('.html') and not filename.startswith('._')): 
     print filename; 
     with open('../news/article/' + filename, "r") as f: 
      page=f.read(); 
     tree=html.fromstring(page); 
     maincontent = stringify_children(tree); 
     print maincontent; 

我的最终目标是能够得到在一个字符串输出到本地文件,因为只有该专区。

下面是一个示例文件:

<html> 

<head> 
    <title>Title</title> 
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css"> 
</head> 

<body> 
    <div class="container"> 
     <div class="row"> 
      <div class="col-xs-4"> 
       <div class="left-bar"></div> 
      </div> 
      <div class="col-xs-4"> 
       <div class="middle-bar"></div> 
      </div> 
      <div class="col-xs-4"> 
       <div class="right-bar"></div> 
      </div> 
     </div> 
     <div class="row"> 
      <div class="col-xs-3"> 
       <div class="navigation"></div> 
      </div> 
      <div class="col-xs-9"> 
       <div class="main-content"> 
        Hello 
        <br> 
        <br><a href="http://www.stackexchange.com">Click here to visit stack exchange</a> 
        <h1>This is an introduction</h1> 
        <h3>This is the third header</h3> 
        <p>Lorem ipsum dolor sit amet.....</p> 
        <p>Lorem ipsum dolor sit amet.....</p> 
        <p>Lorem ipsum dolor sit amet.....</p> 
        <ul> 
         <li>list text</li> 
         <li>list text</li> 
         <li>list text</li> 
         <li>list text</li> 
        </ul> 
        <div class="row"> 
         <div class="col-xs-4"><img src="#">More content 1</div> 
         <div class="col-xs-4"><img src="#">More content 2</div> 
         <div class="col-xs-4"><img src="#">More content 3</div> 
        </div> 

       </div> 
      </div> 
     </div> 
    </div> 

</body> 

</html> 

我想抓住所有的搜索Maincontent类下面的内容。下面是类的在该文件中的XPath:

的XPath:/ HTML /体/ DIV/DIV [2]/DIV [2] /格

程序应该输出以下:

    Hello 
        <br> 
        <br><a href="http://www.stackexchange.com">Click here to visit stack exchange</a> 
        <h1>This is an introduction</h1> 
        <h3>This is the third header</h3> 
        <p>Lorem ipsum dolor sit amet.....</p> 
        <p>Lorem ipsum dolor sit amet.....</p> 
        <p>Lorem ipsum dolor sit amet.....</p> 
        <ul> 
         <li>list text</li> 
         <li>list text</li> 
         <li>list text</li> 
         <li>list text</li> 
        </ul> 
        <div class="row"> 
         <div class="col-xs-4"><img src="#">More content 1</div> 
         <div class="col-xs-4"><img src="#">More content 2</div> 
         <div class="col-xs-4"><img src="#">More content 3</div> 
        </div> 
+0

所以你不想在div本身?这会给你破坏HTML你确定你想要吗? –

+0

是的。我确定,因为我将把数据导入已经创建了该标签的新html文档。 –

回答

0

你可以尝试使用BeautifulSoup。我不是真正的精通它,但你可以做这样的事情(或清洁剂,如果你在阅读BeautifulSoup了:)

from bs4 import BeautifulSoup 
soup = BeautifulSoup(open("input.html"), 'html') 
x = soup.find_all(class_="main-content") 
for line in x[0].contents: 
    print line, 

你会得到这样的输出:

 Hello 
     <br/> 
<br/> <a href="http://www.stackexchange.com">Click here to visit stack exchange</a> 
<h1>This is an introduction</h1> 
<h3>This is the third header</h3> 
<p>Lorem ipsum dolor sit amet.....</p> 
<p>Lorem ipsum dolor sit amet.....</p> 
<p>Lorem ipsum dolor sit amet.....</p> 
<ul> 
<li>list text</li> 
<li>list text</li> 
<li>list text</li> 
<li>list text</li> 
</ul> 
<div class="row"> 
<div class="col-xs-4"><img src="#"/>More content 1</div> 
<div class="col-xs-4"><img src="#"/>More content 2</div> 
<div class="col-xs-4"><img src="#"/>More content 3</div> 
</div> 

BeautifulSoup将“修复”HTML语法,如从

的变化,并且它将保持元素内部的空间。请参阅该文档就可以在:https://www.crummy.com/software/BeautifulSoup/bs4/doc/

0

使用LXML:

from lxml import html 

xm = html.fromstring(h) 
div = xm.xpath("//div[@class='main-content']")[0] 
print(div.text + "".join(map(html.tostring, div.xpath("./*")))) 

或者:

from lxml import html 

xm = html.fromstring(h) 
eles = xm.xpath("//div[@class='main-content']/text() | //div[@class='main-content']/*") 
print("".join([ele if isinstance(ele, str) else html.tostring(ele) for ele in eles])) 
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