获取价值

我有一个JSON对象，像这样获取价值

[ 
    [ 
    { 
     "class":"com.ehealth.data.Sample_Data", 
     "collectedBy":"2013-07-21", 
     "collectedDate":"Kamal", 
     "orderID":2, 
     "sampleID":2.897033553E9 
    }, 
    { 
     "class":"com.ehealth.data.Order_Data", 
     "doctorUsername":"Kamal", 
     "dueDate":"2014-01-02", 
     "orderDate":"2013-12-12", 
     "orderID":2, 
     "patientID":"P0001", 
     "prority":1, 
     "status":"complete", 
     "testType":"Fasting Blood Sugar" 
    } 
    ], 
    [ 
    { 
     "class":"com.ehealth.data.Sample_Data", 
     "collectedBy":"2013-07-22", 
     "collectedDate":"Kamal", 
     "orderID":3, 
     "sampleID":5.978956192E9 
    }, 
    { 
     "class":"com.ehealth.data.Order_Data", 
     "doctorUsername":"Kamal", 
     "dueDate":"2014-01-02", 
     "orderDate":"2013-12-12", 
     "orderID":3, 
     "patientID":"P0001", 
     "prority":2, 
     "status":"complete", 
     "testType":"Fasting Blood Sugar" 
    } 
    ] 
]

和我进行译码后，PHP数组

$data['query'] = json_decode($curl_response);

我尝试访问valuse这样

foreach ($query as $row) { 
    echo $row->sampleID;   
}

但是当我要访问里面的值我不能访问我得到一个错误

A PHP Error was encountered 

Severity: Notice 

Message: Trying to get property of non-object

任何人都可以帮助我。我不知道该怎么办

来源

2013-07-22 Kamal Upasena

请出示您从$获取值数据[“查询”];即的var_dump（$数据[“查询”] ）; – ABorty

我增加了输出到我的问题 –

你可以得到它：

foreach ($query as $row) { 
    echo $row[0]->sampleID;   
}

来源

2013-07-22 07:22:15 Bora

它工作正常，但在第二次迭代时，它给了我错误未定义的属性：stdClass :: $ sampleID –

更新，请再试一次请 – Bora

thanx Bora它工作正常 –

<?php 
$str = '[[{"class":"com.ehealth.data.Sample_Data","collectedBy":"2013-07-21","collectedDate":"Kamal","orderID":2,"sampleID":2.897033553E9},{"class":"com.ehealth.data.Order_Data","doctorUsername":"Kamal","dueDate":"2014-01-02","orderDate":"2013-12-12","orderID":2,"patientID":"P0001","prority":1,"status":"complete","testType":"Fasting Blood Sugar"}],[{"class":"com.ehealth.data.Sample_Data","collectedBy":"2013-07-22","collectedDate":"Kamal","orderID":3,"sampleID":5.978956192E9},{"class":"com.ehealth.data.Order_Data","doctorUsername":"Kamal","dueDate":"2014-01-02","orderDate":"2013-12-12","orderID":3,"patientID":"P0001","prority":2,"status":"complete","testType":"Fasting Blood Sugar"}]]'; 

$json = json_decode($str,true); 

foreach ($json as $datas){ 
    foreach ($datas as $data){ 
     echo (isset($data['sampleID']) ? $data['sampleID'] :'')."<br/>"; 
    } 
} 

echo '<pre>'; 
print_r ($json); 
echo '</pre>'; 
// exit; 

?>

来源

2013-07-22 07:22:03

回答

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