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我最近在c语言中使用过gtk +。在gtk中打印对话框中的输入框的值c
我试图在一个对话框而不是在主窗口(like here)两个回调之间进行通信。但是,与链接中的解决方案不同,该程序会压碎(在第二次回调中,当我尝试使用从参数获得的小部件时)。
这是我这段代码:
#include <gtk/gtk.h>
#include <stdlib.h>
#include <stdio.h>
static void print_text (GtkWidget *widget, gpointer data)
{
GtkEntry* entry = data;
printf("%s", gtk_entry_get_text(entry));
}
static void open_dialog (GtkWidget *widget, gpointer data)
{
GtkWidget *window = data;
GtkWidget *dialog;
GtkWidget *content_area;
GtkWidget *grid;
GtkWidget *label;
GtkWidget *button;
static GtkEntry *textbox;
dialog = gtk_dialog_new_with_buttons ("Get Text",
window,
GTK_DIALOG_MODAL,
GTK_STOCK_OK,
GTK_RESPONSE_OK,
NULL);
content_area = gtk_dialog_get_content_area (GTK_DIALOG (dialog));
grid = gtk_grid_new();
gtk_container_add (GTK_CONTAINER (content_area), grid);
label = gtk_label_new("Value: ");
gtk_grid_attach(GTK_GRID(grid), label, 0, 0, 1, 1);
textbox = gtk_entry_new();
gtk_entry_set_text(textbox, "<Value>");
gtk_grid_attach(GTK_GRID(grid), textbox, 1, 0, 1, 1);
gtk_widget_show_all (dialog);
g_signal_connect (GTK_DIALOG (dialog), "response", G_CALLBACK (print_text), textbox);
}
static void activate (GtkApplication *app, gpointer user_data)
{
GtkWidget *window;
GtkWidget *button;
GtkWidget *entry;
GtkWidget *grid;
window = gtk_application_window_new (app);
gtk_window_set_title (GTK_WINDOW (window), "Window");
gtk_container_set_border_width (GTK_CONTAINER (window), 10);
grid = gtk_grid_new();
gtk_container_add (GTK_CONTAINER (window), grid);
button = gtk_button_new_with_label ("Print Text");
g_signal_connect (button, "clicked", G_CALLBACK (open_dialog), window);
gtk_grid_attach (GTK_GRID (grid), button, 0, 1, 1, 1);
gtk_widget_show_all (window);
}
int main (int argc, char **argv)
{
GtkApplication *app;
int status;
app = gtk_application_new ("org.gtk.example", G_APPLICATION_FLAGS_NONE);
g_signal_connect (app, "activate", G_CALLBACK (activate), NULL);
status = g_application_run (G_APPLICATION (app), argc, argv);
g_object_unref (app);
return status;
}
该方案应该已经印在输入框中的值对话框中关闭对话框后。注意:在主窗口中有一个打开对话框的按钮。
感谢您的帮助!
@josé-也许你可以帮我吗? –