SQL：与相应的日期以及选择列最大值

Question

任何人都知道我怎么可以得到相当于每game_id最大比分的日期，每级请：

---------------------------------------- 
|id |game_id |level |score |date  | 
---------------------------------------- 
|1 |0  |1  |90 |1391989720 | 
|1 |0  |1  |95 |1391989721 | 
|1 |1  |1  |4  |1391989722 | 
|1 |1  |1  |8  |1391989723 | 
|1 |1  |2  |6  |1391989724 | 
---------------------------------------- 

感谢乡亲，应该检查相关注释。此查询工作：

SELECT cdu_user_progress.game_id, 
      cdu_user_progress.level, 
      max_score, 
      cdu_user_progress.date 
    FROM 
    (
     SELECT game_id, level, MAX(score) AS max_score 
     FROM cdu_user_progress 
     GROUP BY game_id, level 
    ) AS ms 
    JOIN cdu_user_progress ON cdu_user_progress.game_id = ms.game_id AND 
           cdu_user_progress.level = ms.level AND 
           cdu_user_progress.score = ms.max_score 

现在，如果我还想要得到的分数（每级）第一game_id和它的日期，拿到这个输出：

----------------------------------------------------------------- 
|game_id |level |max_score |max_date |first_score |first_date | 
----------------------------------------------------------------- 
|0  |1  |95  |1391989721 |90   |1391989720 | 
|1  |1  |8   |1391989723 |4   |1391989722 | 
|1  |2  |6   |1391989724 |6   |1391989724 | 
----------------------------------------------------------------- 

谢谢！

Answer 1

因为它是MySQL，你可以简单地这样对拉动全行平均每场得分最高：

select * from (
    select * 
    from cdu_user_progress 
    order by score desc) x 
group by game_id 

这由功能工作，因为MySQL的非标组，由此返回第一每个组遇到的行不是全部非聚合列是在group by子句中命名的。