LEFT JOIN两个表具有相同的列名，并用PHP

Question

打印出来，我有两个表我的MySQL数据库：

USERS ('id_user' - 'id_client' -> the same as the id in CLIENTS) 
CLIENTS ('id_client' - 'name' etc.) 

我想打印所有的客户和各个用户。这是我的查询：

SELECT * FROM clients AS c LEFT JOIN users AS u ON c.id_client = u.id_client 

这似乎是确定的，但我有麻烦时，我尝试从表clients打印的id_client。我如何使用PHP打印它们？看起来他们是空的......我的查询是否错误？

Answer 1

尝试，

无论GROUP BY或DISTINCT需要

SELECT * FROM clients AS c LEFT JOIN users AS u ON c.id_client = u.id_client GROUP BY c.id_client 

Answer 2

比

简单，只要做到以下几点：

SELECT c.*, u.name FROM clients AS c LEFT JOIN users AS u ON c.id_client = u.id_client 

这将选择一切从表C的，只有名字来自表u。你遇到的问题是你从两个表中选择id_client，这是不必要的，并且在尝试使用php引用时会引起混淆。

Answer 3

SELECT c。 ，u。 FROM clients c LEFT outer JOIN users u ON c.id_client = u.id_client

Answer 4

由于您在两个表（“id_client”）中都有相同名称的字段，所以您必须指定要打印哪一个。

像这样：

SELECT u.id_client, c.id_client, ... FROM clients AS c LEFT JOIN users AS u ON c.id_client = u.id_client