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我试图从MySQL调用存储过程并取回两个OUT参数(@eset和@leng)。我想将这两个参数回显给JavaScript,其中我有一个XMLHttpRequest等待结果。通过PHP调用MySQL存储过程时出错
我得到这个错误:
Strict standards: mysqli::next_result(): There is no next result set.
这里是我的代码:
<?php
//get the q parameter from URL
$q=$_GET["q"];
$eset= "";
$length= 0;
// Opens a connection to a MySQL server
$db= new mysqli('localhost', 'db_name', 'pass');
if (!$db) { die('Not connected : ' . mysql_error());}
// Set the active MySQL database
$db_selected = $db->select_db('db_name');
if (!$db_selected) {
die ('Can\'t use db : ' . mysql_error());
}
// Select all the rows in the markers table
$db->multi_query("CALL mst2($q, @eset, @leng);SELECT @eset as eset;SELECT @leng as length");
$db->next_result(); // flush the null RS from the call
$eset=$db->store_result(); // get the RS containing the id
//echo $eset->fetch_object()->eset, "\n";
$length= $db->store_result();
//echo $length->fetch_object()->leng, "\n";
$response= $eset.$length;
//$eset->free();
//$length->free();
//$response=str_shuffle($q);
//output the response
echo $response;
?>