压扁元组列表

Question

如何循环遍历元组列表中的所有元素到空列表中？

例如：

tup_Before = [(69592, 69582), (69582, 69518), (69518, 69532), (69532, 69525)] 

tup_After = [69592, 69582, 69582, 69518, 69518, 69532, 69532, 69525] 

Answer 1

列表理解：

tup_after = [v for t in tup_Before for v in t] 

，或者使用itertools.chain.from_iterable()：

from itertools import chain 
tup_after = list(chain.from_iterable(tup_Before)) 

演示：

>>> tup_Before = [(69592, 69582), (69582, 69518), (69518, 69532), (69532, 69525)] 
>>> [v for t in tup_Before for v in t] 
[69592, 69582, 69582, 69518, 69518, 69532, 69532, 69525] 
>>> from itertools import chain 
>>> list(chain.from_iterable(tup_Before)) 
[69592, 69582, 69582, 69518, 69518, 69532, 69532, 69525] 

Answer 2

还可以，至少明确的答案：

[l for l in l for l in l] 

其中l是您可以尝试使用itertools.chain()和拆包与*列表名称

Answer 3

：

import itertools 

new_tup = list(itertools.chain(*tup_before)) 

演示：

>>> print new_tup 
[69592, 69582, 69582, 69518, 69518, 69532, 69532, 69525]